The two-way table is attached.
We know that 63 people took the survey, and 22 of them were left-handed. This means that 63-22=41 of them are right handed.
Out of the 63 total, 37 are left brain dominant; this means that 63-37=26 are right brain dominant.
Of the 26 that are right brain dominant, 21 are right handed; this means 26-21=5 are left handed.
Of the 22 left-handed people, 5 are right brain dominant; this means 22-5 = 17 are left brain dominant.
Of the 37 left brain dominant people, 17 are left handed; this means 37-17=20 are right handed.
Set x as adult tickets.
Set y as children's tickets.
x + y = 15
30x + 20y = 270
Solve for x in the first equation.
x + y = 15
x = 15 - y
Plug this into the second equation.
30x + 20y = 270
30(15 - y) + 20y = 270
450 - 30y + 20y = 270
450 - 10y = 270
-10y = -180
y = 18
If there is 18 childrens tickets, there should be -3 adult tickets.
This is impossible, and this impossible answer occured because the question is written wrong.
There are a total of 15 tickets
The smallest costing ticket is the childrens ticket, which costs 20$.
If he only bought children tickets, this would be 20x15 which is 300$.
300$ is over 270$, which makes the question impossible.
Hello :
the nth term ( general term of an arithmetic sequence is :
An =A1+(n-1)d ....a common difference is : d , A1 : the first terme
A1 = 5 and : d = 1 - 5 = - 4 n = 21
A21 = 5 + (21 -1)(-4)
A21 = 5 - 80 = -75
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Your answer will be y= 4/5