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3 years ago

The end of a cave is 380 below

Mathematics

1 answer:

noname [10]3 years ago

8 0

Correct!! Yes it must be you said it

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A pair of fair dice is rolled and the sun is noted. Determine the probability that one die resulted in a 5 given that the sum is

aalyn [17]

There are 36 possible outcomes. Two of these outcomes have a 3 and a 5. Therefore the required probability is 1/18.

8 0

3 years ago

Choose all the values of a that make the following equation true= 3/4 = a/36

exis [7]

Answer:

a = 27

Step-by-step explanation:

3/4 = a/36 Cross multiply

4*a = 36*3 Combine the right

4a = 108 Divide by 4

4a/4 = 108/4

a = 27

5 0

3 years ago

If you bought a hamburger for $10.25 and a soda for $4.53 and had $9 left over, then how much money did you originally have?

Marat540 [252]

$23.78 you originally had

7 0

3 years ago

By which rule are these triangles congruent?<br> A) AAS <br> B) ASA <br> C) SAS <br> D) SSS

Veronika [31]

Answer:

the answer is c)SAS

Step-by-step explanation:

as the sides are already given and and both angles will be equal as vertically opposite angles (VOA)are always equal.

3 0

4 years ago

If the numerator of a fraction is increased by six, the value of the fraction will increase by one. If the denominator of the or

Alchen [17]

Answer:

$\dfrac{7}{6}$

Step-by-step explanation:

Let $\dfrac{a}{b}$ be the original fraction.

If the numerator of a fraction is increased by six, the value of the fraction will increase by one. Hence,

$\dfrac{a+6}{b}=\dfrac{a}{b}+1$

If the denominator of the original fraction is increased by 36, the value of the original fraction will decrease by one. Hence,

$\dfrac{a}{b+36}=\dfrac{a}{b}-1$

Add these two equalities:

$\dfrac{a+6}{b}+\dfrac{a}{b+36}=\dfrac{a}{b}+1+\dfrac{a}{b}-1\\ \\\dfrac{a+6}{b}+\dfrac{a}{b+36}=2\dfrac{a}{b}\\ \\\dfrac{a}{b+36}=\dfrac{2a-(a+6)}{b}\\ \\\dfrac{a}{b+36}=\dfrac{a-6}{b}\\ \\ab=(a-6)(b+36)\\ \\ab=ab+36a-6b-216\\ \\36a-6b-216=0\\ \\6a-b-36=0\\ \\b=6a-36$

Substitute it into the first equation:

$\dfrac{a+6}{6a-36}=\dfrac{a}{6a-36}+1\\ \\\dfrac{a+6}{6(a-6)}=\dfrac{a}{6(a-6)}+1\\ \\a+6=a+6(a-6)\\ \\a+6=a+6a-36\\ \\6a=6+36\\ \\6a=42\\ \\a=7\\ \\b=6\cdot 7-36=42-36=6$

Thus, the initial fraction was

$\dfrac{7}{6}$

6 0

4 years ago