All categories

3 years ago

Determine the rate of reaction that follows the rate= k[A]^m[B]^n

Chemistry

1 answer:

FrozenT [24]3 years ago

5 0

rate=0.2*3^1*3^2=0.2*3*9=5.4(mol/L)s so the correct answer is C.

You might be interested in

In the chemical reaction C + H20 = CO + H2, what are the

drek231 [11]

B , your products are on the right side of the reaction. The reactants are on the left side

7 0

3 years ago

A jogger runs at an average speed of 5.9 mi/h.

madreJ [45]

She will cover distance in 3 days and 16 hours .the time will be 3:15 am on the fourth day.

Convert 5.9 miles/hour to feet/hour there are 5,280 feet in a mile

total distance covered = 47500

distance = rate x time

now, time = 47500/5280

time = 88 hours

88 hours = 3 Days and 16 Hours.

now the time will be 3 :15 am on the fourth day.

The overall distance the object covers in a given amount of time is its average speed. A scalar value represents the average speed. It has no direction and is indicated by the magnitude.

The distance traveled divided by the time taken is the most popular formula for calculating average speed. The alternative formula is to add the initial and final speeds together, then divide by 2.

Learn more about distance time problems here: -

brainly.com/question/13269893

#SPJ4

4 0

1 year ago

Which is a characteristic of a strong base

Allisa [31]

The third one, it releases H+ions into a solution.

7 0

3 years ago

How many moles of sodium hydroxide would react with 1 Mole of sulphuric acid?

Paul [167]

Answer:

Two moles.

Explanation:

Sulphuric (sulfuric) acid $\rm H_2SO_4$ is a diprotic acid. When one mole of $\rm H_2SO_4$ molecules dissolve in water, two moles of $\rm H^{+}$ ions would be produced.

$\rm H_2SO_4 \to 2\, H^{+} + {SO_4}^{2-}$ .

On the other hand, sodium hydroxide $\rm NaOH$ is a monoprotic base. When one mole of $\rm NaOH$ formula units dissolve in water, only one mole of hydroxide ions $\rm OH^{-}$ would be produced.

$\rm NaOH \to Na^{+} + OH^{-}$ .

Note that $\rm H^{+}$ and $\rm OH^{-}$ react at a one-to-one ratio:

$\rm H^{+} + OH^{-} \to H_2O$ .

As a result, it would take $2\; \rm mol$ of $\rm OH^{-}$ to react with the $\rm 2\; mol$ of $\rm H^{+}$ that was released when $1\; \rm mol$ of $\rm H_2SO_4$ is dissolved in water. Since one mole of $\rm NaOH$ formula units could produce only one mole of $\rm OH^{-}$ , it would take $\rm 2\; mol$ of $\rm NaOH$ formula units to produce that $2\; \rm mol$ of $\rm OH^{-}$ for reacting with $1\; \rm mol$ of $\rm H_2SO_4$ .

3 0

3 years ago

Help me pls rawr uwu SSUsSY

cricket20 [7]

Help 2 what the answer for this?

7 0

2 years ago

Read 2 more answers