A the collisions between water particles and polllen grains
<u>Given information:</u>
Mass of NaCl (m) = 87.75 g
Volume of solution (V) = 500 ml = 0.5 L
Molar mass of NaCl (M) = 58.44 g/mol
<u>To determine:</u>
The molarity of NaCl solution
<u>Explanation:</u>
Molarity is defined as the number of moles of solute(n) dissolved per liter of solution (V)
i.e. M = moles of solute/liters of solution = n/V
Moles of solute (n) = mass of solute (m)/molar mass (M)
moles of NaCl = 87.75 g/58.55 g.mol-1 = 1.499 moles
Therefore,
Molarity of NaCl = 1.499 moles/0.5 L = 2.998 moles/lit ≅ 3 M
<u>Ans: (D)</u>
Answer:
66228
Molecular Formula: TiCl2 or Cl2Ti
Chemical Names: Titanium chloride (TiCl2) 10049-06-6 TiCl2 Titanium(II) chloride dichlorotitanium More...
Molecular Weight: 118.77 g/mol
Dates: Modify: 2019-08-10 Create: 2005-03-26
Explanation:
66228
Molecular Formula: TiCl2 or Cl2Ti
Chemical Names: Titanium chloride (TiCl2) 10049-06-6 TiCl2 Titanium(II) chloride dichlorotitanium More...
Molecular Weight: 118.77 g/mol
Dates: Modify: 2019-08-10 Create: 2005-03-26
