Answer:
The right statement is "The percent transmittance of light, %T, will be higher for Sample 1 compared to Sample 2."
Explanation:
The Beer-Lambert Law states that the absorbance is directly proportional to the concentration of the substance.
Absorbance = εLc
ε: molar absorptivity coeficient
L: optical path length
c: molar concentration
Therefore, if ε and L are the same, the higher the concentration, the higher the absorbance and the lower the transmitance.
Since sample 1 has a higher concentration of CuSO₄ than sample 2, sample 1 has a higher absorbance and lower percent transmittance.
Answer:
320 mmol
Explanation:
405.0 mL * 1L/1000 mL = 0.4050 L
0.79 M = 0.79 mol/L
0.79 mol/L * 0.4050 L=0.32 mol
0.32 mol * 10^3 mmol/1 mol = 320 mmol
<span>Data collected from many experiments could not be explained using waves.</span>
Answer : The property in the wrong column is, base form hydrogen gas with metals
Explanation :
Acid : It is a substance that has ability of donating a proton or hydrogen ion,
.
The properties of an acid are :
- Acids are sour in taste.
- It conduct electricity.
- The texture of an acid solution is sticky.
- It react with carbonates to give salt.
- It changes the color of the litmus paper to red.
- It react with a metal to give compound and hydrogen gas.
Base : It is a substance that has ability of donating hydroxide ion,
.
The properties of an base are :
- Base are bitter in taste.
- It conduct electricity.
- The texture of an base solution is slippery.
- It changes the color of the litmus paper to blue.
- It does not react with a metal.
Hence, from the above information, we conclude that the property in the wrong column is, base form hydrogen gas with metals
.
0,35 kmol/m³ = 0,35 mol/dm³ = 0,35 mol/L
175 mL = 0,175 L
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C = n/V
n = 0,35×0,175
n = 0,06125 mol
mCa(NO₃)₂: 40+(14×2)+(16×6) = 164 g/mol
1 mol --------- 164g
0,06125 ---- X
X = 10,045g
To prepare 175 mL of 0,35M solution, add 10,045g of calcium nitrate and add water to a volume of 175ml.