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Andre45 [30]
3 years ago
8

A topic list is a list of important content and material which will be covered on a test.   Please select the best answer from t

he choices provided T or F
Physics
2 answers:
Sindrei [870]3 years ago
8 0

Answer:

True on e2020

Explanation:

just took the test!

Iteru [2.4K]3 years ago
6 0
Sounds T to me. My teacher used to give those out.
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How did scientists discover the Earth had a liquid outer core and solid inner core?
viktelen [127]
Dr. Inge discovered the make up of the earths inner core by studying how an earthquakes waves bounced off the core. And Inge Lehmann was studying the waves of a 1929 earthquake when she found them acting inconsistently with solid mantle crust 
hope it helps you


6 0
4 years ago
Infer why the output force exerted by a rake must be less than input force?
adell [148]
<h3><u>Answer and Explanation</u>;</h3>
  • input force refers to the force exerted on a machine, also known as the effort, while the output force is the force machines produce or the Load. The ratio of output force to input force gives the mechanical advantage of a simple machine
  • <em><u>The output force exerted by the rake must be less than the input force because one has to use force while raking. The force used to move the rake is the input force. </u></em>
  • <em><u>The rake is not going to be able to convert all of the input force into output force, the force the rake applies to move the leaves, because of friction.</u></em>
5 0
4 years ago
The average distance of the planet mercury from the sun is 0.39 times the average distance of the earth from the sun. How long i
Stels [109]

Answer:

T_1=0.24y

Explanation:

Using Kepler's third law, we can relate the orbital periods of the planets and their average distances from the Sun, as follows:

(\frac{T_1}{T_2})^2=(\frac{D_1}{D_2})^3

Where T_1 and T_2 are the orbital periods of Mercury and Earth respectively. We have D_1=0.39D_2 and T_2=1y. Replacing this and solving for

T_1^2=T_2^2(\frac{D_1}{D_2})^3\\T_1^2=(1y)^2(\frac{0.39D_2}{D_2})^3\\T_1^2=1y^2(0.39)^3\\T_1^2=0.059319y^2\\T_1=0.24y

5 0
3 years ago
A dog, that has a mass of 16 kgs, runs across a yard. What is the average force applied to the dog from the ground as it runs ac
VikaD [51]

Answer:

156.96 N

Explanation:

F=ma where m is the mass and a is acceleration

Substituting 16 Kg for m and 9.81 m/s2 for g then

F=16*9.81= 156.96 N

4 0
3 years ago
Hi i have homework can you help me
soldier1979 [14.2K]

Explanation:

The particle will be at rest when its velocity v(t) is equal to zero. Recall that the velocity is simply the derivative of the position x(t) with respect to time:

v(t) = \dfrac{dx}{dt}

Since x(t) = t^2 - 2t + 2

then

v(t) = \dfrac{d}{dt}(t^2 - 2t + 2) = 2t - 2 = 0

Solving for t, we find that the particle will be at rest at

t = 1\:\text{s}

6 0
3 years ago
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