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viktelen [127]
3 years ago
9

How are the forces between charges similar to the forces between magnetic poles?

Physics
2 answers:
hram777 [196]3 years ago
8 0

Answer:

As we know that the force between two charges and force between two poles are similar in may ways. These are given as following

1). Similar poles and similar charge always repel each other while opposite charge and opposite poles will attract each other

2). force between two charges is given by

F = \frac{kq_1q_2}{r^2}

force between two poles of magnet is given as

F = \frac{\mu_o m_1m_2}{4\pi r^2}

3). Both the force equation follows inverse square law which means force inversely depends on the square of the distance between two charges and two poles

4). Both forces depends on the product of two charges or product of two pole strength of magnet

Dmitriy789 [7]3 years ago
6 0
Https://www.google.com/search?q=How+are+the+forces+between+charges+similar+to+the+forces+between+mag...

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<h3>What is angular momentum.?</h3>

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A copper wire and a tungsten wire of the same length have the same resistance. What is the ratio of the diameter of the copper w
spayn [35]

Answer:

Therefore the ratio of diameter of the copper to that of the tungsten is

\sqrt{3} :\sqrt{10}

Explanation:

Resistance: Resistance is defined to the ratio of voltage to the electricity.

The resistance of a wire is

  1. directly proportional to its length i.eR\propto l
  2. inversely proportional to its cross section area i.eR\propto \frac{1}{A}

Therefore

R=\rho\frac{l}{A}

ρ is the resistivity.

The unit of resistance is ohm (Ω).

The resistivity of copper(ρ₁) is 1.68×10⁻⁸ ohm-m

The resistivity of tungsten(ρ₂) is 5.6×10⁻⁸ ohm-m

For copper:

A=\pi r_1^2 =\pi (\frac{d_1}{2} )^2

R_1=\rho_1\frac{l_1}{\pi(\frac{d_1}{2})^2 }

\Rightarrow (\frac{d_1}{2})^2=\rho_1\frac{l_1}{\pi R_1 }......(1)

Again for tungsten:

R_2=\rho_2\frac{l_2}{\pi(\frac{d_2}{2})^2 }

\Rightarrow (\frac{d_2}{2})^2=\rho_2\frac{l_2}{\pi R_2 }........(2)

Given that R_1=R_2   and    l_1=l_2

Dividing the equation (1) and (2)

\Rightarrow\frac{ (\frac{d_1}{2})^2}{ (\frac{d_2}{2})^2}=\frac{\rho_1\frac{l_1}{\pi R_1 }}{\rho_2\frac{l_2}{\pi R_2 }}

\Rightarrow( \frac{d_1}{d_2} )^2=\frac{1.68\times 10^{-8}}{5.6\times 10^{-8}}   [since R_1=R_2   and    l_1=l_2]

\Rightarrow( \frac{d_1}{d_2} )=\sqrt{\frac{1.68\times 10^{-8}}{5.6\times 10^{-8}}}

\Rightarrow( \frac{d_1}{d_2} )=\sqrt{\frac{3}{10}}

\Rightarrow d_1:d_2=\sqrt{3} :\sqrt{10}

Therefore the ratio of diameter of the copper to that of the tungsten is

\sqrt{3} :\sqrt{10}

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Answer:

It is called a mixture.

Explanation:

A mixture is a physical combination of 2 or more substances that are blended together without forming a new substance.

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