Answer:
The magnetic field along x axis is
![B_{x}=1.670\times10^{-10}\ T](https://tex.z-dn.net/?f=B_%7Bx%7D%3D1.670%5Ctimes10%5E%7B-10%7D%5C%20T)
The magnetic field along y axis is zero.
The magnetic field along z axis is
![B_{z}=3.484\times10^{-10}\ T](https://tex.z-dn.net/?f=B_%7Bz%7D%3D3.484%5Ctimes10%5E%7B-10%7D%5C%20T)
Explanation:
Given that,
Length of the current element ![dl=(0.5\times10^{-3})j](https://tex.z-dn.net/?f=dl%3D%280.5%5Ctimes10%5E%7B-3%7D%29j)
Current in y direction = 5.40 A
Point P located at ![\vec{r}=(-0.730)i+(0.390)k](https://tex.z-dn.net/?f=%5Cvec%7Br%7D%3D%28-0.730%29i%2B%280.390%29k)
The distance is
![|\vec{r}|=\sqrt{(0.730)^2+(0.390)^2}](https://tex.z-dn.net/?f=%7C%5Cvec%7Br%7D%7C%3D%5Csqrt%7B%280.730%29%5E2%2B%280.390%29%5E2%7D)
![|\vec{r}|=0.827\ m](https://tex.z-dn.net/?f=%7C%5Cvec%7Br%7D%7C%3D0.827%5C%20m)
We need to calculate the magnetic field
Using Biot-savart law
![B=\dfrac{\mu_{0}}{4\pi}\timesI\times\dfrac{\vec{dl}\times\vec{r}}{|\vec{r}|^3}](https://tex.z-dn.net/?f=B%3D%5Cdfrac%7B%5Cmu_%7B0%7D%7D%7B4%5Cpi%7D%5CtimesI%5Ctimes%5Cdfrac%7B%5Cvec%7Bdl%7D%5Ctimes%5Cvec%7Br%7D%7D%7B%7C%5Cvec%7Br%7D%7C%5E3%7D)
Put the value into the formula
![B=10^{-7}\times5.40\times\dfrac{(0.5\times10^{-3})\times(-0.730)i+(0.390)k}{(0.827)^3}](https://tex.z-dn.net/?f=B%3D10%5E%7B-7%7D%5Ctimes5.40%5Ctimes%5Cdfrac%7B%280.5%5Ctimes10%5E%7B-3%7D%29%5Ctimes%28-0.730%29i%2B%280.390%29k%7D%7B%280.827%29%5E3%7D)
We need to calculate the value of ![\vec{dl}\times\vec{r}](https://tex.z-dn.net/?f=%5Cvec%7Bdl%7D%5Ctimes%5Cvec%7Br%7D)
![\vec{dl}\times\vec{r}=(0.5\times10^{-3})\times(-0.730)i+(0.390)k](https://tex.z-dn.net/?f=%5Cvec%7Bdl%7D%5Ctimes%5Cvec%7Br%7D%3D%280.5%5Ctimes10%5E%7B-3%7D%29%5Ctimes%28-0.730%29i%2B%280.390%29k)
![\vec{dl}\times\vec{r}=i(0.350\times0.5\times10^{-3}-0)+k(0+0.730\times0.5\times10^{-3})](https://tex.z-dn.net/?f=%5Cvec%7Bdl%7D%5Ctimes%5Cvec%7Br%7D%3Di%280.350%5Ctimes0.5%5Ctimes10%5E%7B-3%7D-0%29%2Bk%280%2B0.730%5Ctimes0.5%5Ctimes10%5E%7B-3%7D%29)
![\vec{dl}\times\vec{r}=0.000175i+0.000365k](https://tex.z-dn.net/?f=%5Cvec%7Bdl%7D%5Ctimes%5Cvec%7Br%7D%3D0.000175i%2B0.000365k)
Put the value into the formula of magnetic field
![B=10^{-7}\times5.40\times\dfrac{(0.000175i+0.000365k)}{(0.827)^3}](https://tex.z-dn.net/?f=B%3D10%5E%7B-7%7D%5Ctimes5.40%5Ctimes%5Cdfrac%7B%280.000175i%2B0.000365k%29%7D%7B%280.827%29%5E3%7D)
![B=1.670\times10^{-10}i+3.484\times10^{-10}k](https://tex.z-dn.net/?f=B%3D1.670%5Ctimes10%5E%7B-10%7Di%2B3.484%5Ctimes10%5E%7B-10%7Dk)
Hence, The magnetic field along x axis is
![B_{x}=1.670\times10^{-10}\ T](https://tex.z-dn.net/?f=B_%7Bx%7D%3D1.670%5Ctimes10%5E%7B-10%7D%5C%20T)
The magnetic field along y axis is zero.
The magnetic field along z axis is
![B_{z}=3.484\times10^{-10}\ T](https://tex.z-dn.net/?f=B_%7Bz%7D%3D3.484%5Ctimes10%5E%7B-10%7D%5C%20T)
I think the correct answer is light energy. It is light energy that is transformed into chemical energy by plants by the process called photosynthesis. In this process, plants<span> take in water, carbon dioxide, and sunlight and </span>turn<span> them </span>into<span> glucose and oxygen.</span>
The FREQUENCY of light remains unchanged once it leaves the source.
<span>electromagnetic.........</span>