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steposvetlana [31]
3 years ago
12

If Scobie could drive a Jetson's flying car at a constant speed of 160.0 km/hr across oceans and space, approximately how long w

ould Scoobie take to drive around Earth's equator in days
Physics
1 answer:
DochEvi [55]3 years ago
6 0

Scobie will take 10 days to drive around Earth's equator.

To calculate the time that takes Scobie to drive around Earth's equator we need to find the distance, which is given by the equation of a circumference:

d = 2\pi r

<em>Where:</em>

r: is the Earth's radius = 6371 km

Then, the distance is:

d = 2\pi r = 2\pi*6371 km = 40030.2 km

Now, if we divide the above distance by the speed of the car we can find the time:

t = \frac{d}{v} = \frac{40030.2 km}{160.0 km/h} = 250.2 h*\frac{1 d}{24 h} = 10 d

Therefore, Scobie will take 10 days to drive around Earth's equator.

     

To learn more about distance and time here: brainly.com/question/14236800?referrer=searchResults

I hope it helps you!

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Answer:

3 units

Solution:

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Square base, with edge a=7 units

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V=Ab h

Ab=49 square units

539 cubic units = (49 square units) h

h= 11 units

s-h=14 units-11 units

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8 0
3 years ago
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A force acts on a body of mass 13 kg initially at rest. The force
PtichkaEL [24]

Answer:

Force that acted on the body was F = 13 N

Explanation:

If once accelerated, the body covers 60 meters in 6 seconds, then its velocity is 60/6 m/s = 10 m/s

When the force was acting (for 10 seconds) the object accelerated from rest (initial velocity vi = 0) to 10 m/s (its final velocity). therefore we can use the kinematic equation for the velocity in an accelerated motion given by:

v_f=v_i+a*t

which in our case becomes;

10\,m/s=0+a*(10\,s)

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Therefore the force acting on the body, based on Newton's 2nd Law expression: F = m * a is:

F = 13 kg * 1 m/s^2 = 13 N

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3 years ago
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Explanation:

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Explanation:

The inertia of a 4 kg mass is four times as great as a 1 kg mass.

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Question 2
yarga [219]

Answer:

24.4 m

Explanation:

first we have to calculate how long the cat will be in the air, in vertical direction this is free fall from 4m (poor cat, hope he survived) with acceleration of g=9.81 m/s^2

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time = sqrt (2 * 4 / 9.81)

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as you are asked to give 3 significant numbers answer is 24,4 m

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2 years ago
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