(0.5)×(0squared)×(3)=(1.5j)
It depends how large the object is. But, if it is 2 by 4, most likely the wood sieges more than the glass.
Hope this helps.
Distance= Time×Speed
= 1800×1.5
= 2700 m
I am not sure it's right. the question itself is confusing.
Answer:
3.1 m/s
Explanation:
First, find the time it takes for the cat to land. Take down to be positive.
Given:
Δy = 0.61 m
v₀ = 0 m/s
a = 9.81 m/s²
Find: t
Δy = v₀ t + ½ at²
(0.61 m) = (0 m/s) t + ½ (9.81 m/s²) t²
t = 0.353 s
Now find the horizontal velocity needed to travel 1.1 m in that time.
Given:
Δx = 1.1 m
a = 0 m/s²
t = 0.353 s
Find: v₀
Δx = v₀ t + ½ at²
(1.1 m) = v₀ (0.353 s) + ½ (0 m/s²) (0.353 s)²
v₀ = 3.1 m/s
Answer:
Yes is large enough
Explanation:
We need to apply the second Newton's Law to find the solution.
We know that,

And we know as well that

Replacing the aceleration value in the equation force we have,

Substituting our values we have,


The weight of the person is then,


<em>We can conclude that force on the ball is large to lift the ball</em>