PH is 7.45. Calculate value of [H3O+] and [OH-]

Chemistry

1 answer:

lana66690 [7]2 years ago

8 0

Answer:

The answer is (H30+) =3,55e-8M and (OH-)=2,82e-7M

Explanation:

We use the formulas:

pH= - log(H30+) and Kwater=(H30+)x(OH-)

pH= - log(H30+) ----< (H30+)= antilog- pH=antilog- 7,45=3,55E-8M

Kwater=(H30+)x(OH-)

(OH-)=Kwater/(H30+)= 1,00e-14/3,55e-8 = 2,82e-7

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Therefore, sodium hydroxide has various acute and chronic health effects.

Learn more about SDS, here:

brainly.com/question/2471127

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