If an atom is located in the 3rd period, which of the following is true:

A mercury manometer is used to measure pressure in the container illustrated. Calculate the pressure exerted by the gas if atmos

Brilliant_brown [7]

Answer:

Pressure exerted by the gas is 574.85 torr

Explanation:

Atmospheric pressure = 751 torr

but 1 torr = 1 mmHg

therefore,

atmospheric pressure = 751 mmHg

1 mmHg = 133.3 Pa

therefore,

atmospheric pressure = 751 x 133.3 = 100108.3 Pa

distance labeled (tube section with mercury) = 176 mm

the pressure within the tube will be

$P_{tube}$ = ρgh

where ρ is the density of mercury = 13600 kg/m^3

h is the labeled distance = 176 mm = 0.176 m

g is acceleration due to gravity = 9.81 m/s^2

$P_{tube}$ = 13600 x 9.81 x 0.176 = 23481.216 Pa

The general equation for the pressure in the manometer will be

$P_{atm}$ = $P_{tube}$ + $P_{gas}$

where $P_{atm}$ is the atmospheric pressure

$P_{tube}$ is the pressure within the tube with mercury

$P_{gas}$ is the pressure of the gas

substituting, we have

100108.3 = 23481.216 + $P_{gas}$

$P_{gas}$ = 100108.3 - 23481.216 = 76627.1 Pa

This pressure can be stated in mmHg as

76627.1 /133.3 = 574.85 mmHg

and also equal to 574.85 torr

6 0

3 years ago

What mass (in g) of potassium chlorate is decomposed if the yield of oxygen gas for the first reaction is 88.6%, if it is known

Ainat [17]

Using the stoichiometry and the number of moles involved in the reaction, The mass of KClO3 decomposed is 63.73 g.

Let us take it up from the second reaction;

Using stoichiometry , the equation of the reaction is;

CH4 + 2O2 ⟶ CO2 + 2H2O

Number of moles of CO2 produced = mass/molar mass

Actual yield of CO2 = 23.6 * 100/77.8 = 30.33 g

Number of moles in 30.33 g of CO2 = 30.33 g/44 g/mol = 0.69 moles

From the reaction equation;

2 moles of O2 yields 1 mole of CO2

x moles of O2 yields 0.69 moles of CO2

x = 2 * 0.69 /1

x = 1.38 moles of O2.

Mass of O2 used = 1.38 moles * 32 g/mol = 44.16 g

This becomes the actual yield of the first reaction.

Theoretical yield of oxygen = 44.16 g * 100/88.6

= 49.84 g of O2

Number of moles of O2 = 49.84 g/32 g/mol = 1.56 moles

Given the reaction equation;

KClO3 ⟶ 2KCl + 3O2

1 mole of KClO3 yields 3 moles of O2

x moles of O2 yields 1.56 moles of O2

x = 1 * 1.56/3

= 0.52 moles of KClO3

Mass of KClO3 decomposed = 0.52 moles * 122.55 g/mol = 63.73 g of KClO3

Learn more: brainly.com/question/9743981

7 0

3 years ago

What mass of fes is formed if 9.42 g of fe reacts with 68.0 g of s8? 8fe(s) + s8(s) â†’ 8fes(s)?

allochka39001 [22]

From the equation, we see that the molar ratio of Fe : S required is:

8 : 1

The moles of Fe present are: 9.42/56 = 0.168
Moles of S = 68/(32 * 8) = 0.265

The molar ratio is:

1 : 1.6

Therefore, iron is the limiting reactant as it is present in a ratio lower than that required. The ratio of

Fe : FeS is
1 : 1

So 0.168 moles of FeS will form. The mass of FeS will be:

Mass = 0.168 * (56 + 32)
Mass = 14.78 grams

14.78 grams of FeS will be formed.

4 0

4 years ago

Apart from plants, what other group of organisms photosynthesises?

Licemer1 [7]

Answer:

Plants, algae, and a group of bacteria called cyanobacteria are the only organisms capable of performing photosynthesis

4 0

2 years ago

What is the main purpose of using NaOH in the saponification reaction . NaOH works as the catalyst b. NaOH solution is the solve

Alex777 [14]

Answer:

C. NaOH acts as a reactant in the reaction

Explanation:

Because during the saponification process, Na+ replaces the H+ in the fatty acid been used for the saponification process

7 0

3 years ago