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2 years ago

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18. What do you call a change in state from a liquid to a gas?

2 answers:

makkiz [27]2 years ago

8 0

ANSWER: vaporization
EXPLANATION: Matter changes between the liquid and gas states through vaporization and condensation. Vaporization As liquid water is heated, its temperature rises. until it reaches 100°C. At this point, liquid water changes into water vapor. The change from a liquid to a gas is known as vaporization

Ket [755]2 years ago

5 0

Answer:

evaporation

Explanation:

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We have a 10kg ball and a 15kg ball. We drop them from the top of the science building while objects are at rest and there is no

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They will hit the ground at the same time, as mass is negligible when calculating the acceleration of gravity when there is no air resistance

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3 years ago

Which property is closely related to its temperature

Lilit [14]

Answer:

Mass – The single most important property that determines other properties of the star. Luminosity – The total amount of energy (light) that a star emits into space. Temperature – surface temperature, closely related to the luminosity and color of the star

Explanation:

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3 years ago

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An electron emitted in the beta decay of bismuth-210 has a mean kinetic energy of 390 keV. (a) Find the de Broglie wavelength of

Sauron [17]

Explanation:

Given that,

The mean kinetic energy of the emitted electron, $E=390\ keV=390\times 10^3\ eV$

(a) The relation between the kinetic energy and the De Broglie wavelength is given by :

$\lambda=\dfrac{h}{\sqrt{2meE}}$

$\lambda=\dfrac{6.63\times 10^{-34}}{\sqrt{2\times 9.1\times 10^{-31}\times 1.6\times 10^{-19}\times 390\times 10^3}}$

$\lambda=1.96\times 10^{-12}\ m$

(b) According to Bragg's law,

$n\lambda=2d\ sin\theta$

n = 1

For nickel, $d=0.092\times 10^{-9}\ m$

$\theta=sin^{-1}(\dfrac{\lambda}{2d})$

$\theta=sin^{-1}(\dfrac{1.96\times 10^{-12}}{2\times 0.092\times 10^{-9}})$

$\theta=0.010^{\circ}$

As the angle made is very small, so such an electron is not useful in a Davisson-Germer type scattering experiment.

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3 years ago

On level ground a shell is fired with an initial velocity of 49.0 m/s at 70.0 โ above the horizontal and feels no appreciable ai

xenn [34]

Answer:

Horizontal component = 16.8 m/s

Vertical component = 46.0 m/s

Explanation:

If we denote the initial velocity by <em>v</em> and the angle above the horizontal by <em>θ</em>,

the horizontal component of this initial velocity is given by

$v_x = v\cos \theta$

$v_x = (49.0\text{ m/s})\cos\,(70.0^\circ) = 16.8\text{ m/s}$

The vertical component is given by

$v_y = v\sin\theta$

$v_x = (49.0\text{ m/s})\sin\,(70.0^\circ) = 46.0\text{ m/s}$

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2 years ago

Calculate Vector component in Y if the hypotenuse is 32 and angle is 45

Lerok [7]

Answer:

The correct option is;

c. 22.6

Explanation:

The given parameters are;

The hypotenuse of the vector = 32

The angle of the vector = 45°

Therefore, the vector component in the y-axis is given as follows;

$v_y = v \times sin(\theta)$

Substituting the values from the question gives;

$v_y = 32 \times sin(45^{\circ}) \approx 22.6$

The vector component in the y-axis, $v_y$ , is approximately 22.6.

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2 years ago