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bulgar [2K]
3 years ago
8

Find the uniform acceleration that causes a car's velocity to change from 20.0 m/s to 105 m/s in and 12.0 s

Physics
1 answer:
Sauron [17]3 years ago
5 0

Answer:

7.08 m/s²

Explanation:

Given:

v₀ = 20.0 m/s

v = 105 m/s

t = 12.0 s

Find: a

v = at + v₀

105 m/s = a (12.0 s) + 20.0 m/s

a = 7.08 m/s²

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3 years ago
After the collision, car 1 has a final velocity of 6m/s south. What is the final velocity of car2?
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3 years ago
Starting fom rest, a car accelerates at a constant rate, reaching 88 km/h in 12 s. (a) What is its acceleration? (b) How far doe
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Answer:

(A)  a=2.0.37m/sec^2

(B) s = 146.664 m

Explanation:

We have given car starts from the rest so initial velocity u = 0 m /sec

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We know that 1 km = 1000 m

And 1 hour = 3600 sec

So 88km/hr=88\times \frac{1000}{3600}=24.444m/sec

Time is given t = 12 sec

(A) From first equation of motion v = u+at

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