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3 years ago

What is the current in a 160V circuit if the resistance is 2Ω? V= I= R =

Physics

1 answer:

sveta [45]3 years ago

8 0

Answer:

80 amperes

Explanation:

Current in the circuit = ?

Voltage in the circuit = 160 Volts

Resistance = 2 Ω

Voltage = Current x Resistance

V = IR

160V = I x 2 Ω

I = 160V / 2 Ω

I = 80 Amperes

Therefore the current in the circuit is 80 amperes :)

You might be interested in

a car drives 40 miles east, turns around, then drives 30 miles west. (a) Find the distance traveled by the car. (b) find the car

Dovator [93]

Part A)

Distance is given as sum of total path length

So here as we are given that car drives 40 miles East and 30 miles West

So here the total path length is

$Distance = 40 miles + 30 miles$

$distance = 70 miles$

Part B)

Displacement is given as straight line distance between initial and final position

So here we can see that

$d_1 = 40 miles$ East

$d_2 = 30 miles$ West

Now the total displacement will be

$d = d_1 - d_2 = 40 - 30 = 10 miles$

<u><em>so the displacement will be 10 miles East</em></u>

8 0

3 years ago

What is the frequency of a wave if the speed of the wave is 7.9m/s and the wavelength is 3.1m?

Tpy6a [65]

Answer:

Explanation:

The frequency of the wave given it's velocity and wavelength can be found by using the formula

$f = \frac{c}{ \lambda} \\$

where

c is the velocity of the wave in m/s

$\lambda$ is the wavelength in m

From the question

c = 7.9 m/s

$\lambda$ = 3.1 m

We have

$f = \frac{7.9}{3.1} = 2.548387... \\$

We have the final answer as

Hope this helps you

6 0

2 years ago

A 175 g ball on the end of a 0.5 m light string is revolving uniformly at 2 rev/s. what is the ball's acceleration and string's

BARSIC [14]

Hope it cleared your doubt.

3 0

3 years ago

a body of mass 0.2kg is whirled round a horizontal circle by a string inclined at 30 degrees to the vertical calculate <br /&

Katen [24]

Answer:

a) T = 2.26 N, b) v = 1.68 m / s

Explanation:

We use Newton's second law

Let's set a reference system where the x-axis is radial and the y-axis is vertical, let's decompose the tension of the string

sin 30 = $\frac{T_x}{T}$

cos 30 = $\frac{T_y}{T}$

Tₓ = T sin 30

T_y = T cos 30

Y axis

T_y -W = 0

T cos 30 = mg (1)

X axis

Tₓ = m a

they relate it is centripetal

a = v² / r

we substitute

T sin 30 = m $\frac{v^2}{r}$ (2)

a) we substitute in 1

T = $\frac{mg }{cos 30}$

T = $\frac{ 0.2 \ 9.8}{cos \ 30}$

T = 2.26 N

b) from equation 2

v² = $\frac{T \ sin 30 \ r}{m}$

If we know the length of the string

sin 30 = r / L

r = L sin 30

we substitute

v² = $\frac{ T \ sin 30 \ L \ sin 30}{m}$

v² = $\frac{TL \ sin^2 30}{m}$

For the problem let us take L = 1 m

let's calculate

v = $\sqrt{ \frac{2.26 \ 1 \ sin^230}{0.2} }$

v = 1.68 m / s

8 0

3 years ago

an object with a mass of 5kg is moving with an initial velocity of 20m/s.the object accelerates at a rate of 15m/s/s for 8s.what

Alinara [238K]

It doesn't matter what the object's initial velocity is, or how long
the acceleration lasts. All that matters is the object's mass and
acceleration.

Force = (mass) x (acceleration) =

(5kg) x (15 m/s²) =

75 kg-m/s² = <em>75 newtons .</em>

5 0

3 years ago