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Fittoniya [83]
2 years ago
11

5. Kelvin applied a rightward force of 302 N to a 29 kg desk to accelerate it across the floor. The

Physics
1 answer:
Naddik [55]2 years ago
3 0

The force of friction is 213.2 N

Explanation:

The frictional force acting on an object sliding on a surface is given by:

F_f = \mu mg

where:

\mu is the coefficient of friction

m is the mass of the object

g is the acceleration of gravity

In this problem we have

\mu=0.750

m = 29 kg

g=9.8 m/s^2

Therefore, the force of friction is

F_f = (0.750)(29)(9.8)=213.2 N

Learn more about friction:

brainly.com/question/6217246

brainly.com/question/5884009

brainly.com/question/3017271

brainly.com/question/2235246

#LearnwithBrainly

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tia_tia [17]

Answer:

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a) In the problem the force is nonlinear and they ask us for work, so we must use it's definition

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    W = 7.5 - 0.75

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    W = ΔK = ½ m v² -0

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    v = √(2 6.75/ 0.90)

    v = 3.87 m / s

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