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3 years ago

5. Kelvin applied a rightward force of 302 N to a 29 kg desk to accelerate it across the floor. The

Physics

1 answer:

Naddik [55]3 years ago

3 0

The force of friction is 213.2 N

Explanation:

The frictional force acting on an object sliding on a surface is given by:

$F_f = \mu mg$

where:

$\mu$ is the coefficient of friction

m is the mass of the object

g is the acceleration of gravity

In this problem we have

$\mu=0.750$

m = 29 kg

$g=9.8 m/s^2$

Therefore, the force of friction is

$F_f = (0.750)(29)(9.8)=213.2 N$

Learn more about friction:

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Which mixtures could be separated using evaporation? Check all that apply. fat in milk salt in ocean water mud in pond water but

salantis [7]

I would go with salt in ocean water as when you heat it and the water begins to evaporate it will leave the salt behind

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BRAINLIEST IF HELPED

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4 years ago

Read 2 more answers

How long does it take an airplane to fly 5000 m if it maintains a speed of 240 meters per second?

kolbaska11 [484]

Answer:

20 5/6 sec

Explanation:

To find the solution we divide 5000 by 240

However, when you see a problem, always try to simplify

5000/240=500/24=250/12=125/6

Now the division is much easier

20 5/6 sec

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3 years ago

6. One minute after takeoff, a rocket carrying the space shuttle into outer space reaches a speed of 447 m/s.

Sidana [21]

Answer:

acceleration of the rocket is given as

$a = 7.45 m/s^2$

Explanation:

As we know that rocket starts from rest and then reach to final speed of 447 m/s after t = 1 min

so we have

$v_i = 0$

$v_f = 447 m/s$

$t = 1 min = 60 s$

so we have

$a = \frac{v_f - v_i}{t}$

$a = \frac{447 - 0}{60}$

$a = 7.45 m/s^2$

7 0

3 years ago

If you were to triple the size of the Earth (R = 3R⊕) and double the mass of the Earth (M = 2M⊕), how much would it change the g

EastWind [94]

Answer:

Decreased by a factor of 4.5

Explanation:

"We have Newton formula for attraction force between 2 objects with mass and a distance between them:

$F_G = G\frac{M_1M_2}{R^2}$

where $G =6.67408 × 10^{-11} m^3/kgs^2$ is the gravitational constant on Earth. $M_1, M_2$ are the masses of the object and Earth itself. and R distance between, or the Earth radius.