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Gwar [14]
2 years ago
10

The average 8- to 18-year-old spends __________ per day on average in front of a screen doing very little to no physical activit

y. A. 0 hours B. 30 minutes C. 1 hour D. 3 hours or more Please select the best answer from the choices provided. A B C D
Physics
1 answer:
natta225 [31]2 years ago
5 0

Answer:

D. 3 hours or more

Explanation:

The average 8- to 18-year-old spends at least D. 3 hours every day in front of a screen, performing little to no physical activity. This is because, instead of exercising and socializing with their peers, children and teenagers frequently talk, watch a lot of movies/shows, or play video games on their computers. Unfortunately, this is typically considerably more than three hours every day. Although some children still prefer physical activities over this, the bulk of the population does not.

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An atom is the most __________ unit of living and nonliving things.
storchak [24]
Basic is the answer. (i think so) 
7 0
4 years ago
Read 2 more answers
An object starts at Xi = -4m with an initial velocity of 4m/s. It experiences an acceleration of -2 m/s^2 for 2 seconds, followe
GalinKa [24]

Answer:

a) 0 m/s

b) - 24 m/s

c)  - 68 m

Explanation:

Given:

Initial distance = - 4 m

Initial velocity, u = 4 m/s

1) acceleration, a = - 2 m/s² for time, t = 2 seconds

thus,

velocity after 2 seconds will be

from Newton's equation of motion

v = u + at

v = 4 + (-2) × 2

v = 0 m/s

2) Velocity after 2 second is the initial velocity for this case

given acceleration = - 6 m/s² for 4 seconds

thus,

final velocity, v = 0 + ( - 6 ) × 4 = - 24 m/s

here the negative sign depicts the velocity in opposite direction to the initial direction of motion

thus, velocity after 6 seconds = - 24 m/s

3) Now,

Total displacement in 6 seconds

= Displacement in 2 seconds + Displacement in 4 seconds

From Newton's equation of motion

s=ut+\frac{1}{2}at^2

where,  

s is the distance

u is the initial speed  

a is the acceleration

t is the time

thus,

= 0\times2+\frac{1}{2}\times(-2)\times2^2  + 0\times4+\frac{1}{2}\times-6\times4^2

= - 16 - 48

= - 64 m

Hence, the final displacement = - 64 - 4 = - 68 m

5 0
3 years ago
On a distance vs. time graph, how do you know when the object is moving away from its starting position?
Ainat [17]
U know by if they are in first place
8 0
3 years ago
Read 2 more answers
If the cold temperature reservoir of a Carnot engine is held at a constant 306 K, what temperature should the hot reservoir be k
Paraphin [41]
Efficiency η of a Carnot engine is defined to be: 
<span>η = 1 - Tc / Th = (Th - Tc) / Th </span>
<span>where </span>
<span>Tc is the absolute temperature of the cold reservoir, and </span>
<span>Th is the absolute temperature of the hot reservoir. </span>

<span>In this case, given is η=22% and Th - Tc = 75K </span>
<span>Notice that although temperature difference is given in °C it has same numerical value in Kelvins because magnitude of the degree Celsius is exactly equal to that of the Kelvin (the difference between two scales is only in their starting points). </span>

<span>Th = (Th - Tc) / η </span>
<span>Th = 75 / 0.22 = 341 K (rounded to closest number) </span>
<span>Tc = Th - 75 = 266 K </span>

<span>Lower temperature is Tc = 266 K </span>
<span>Higher temperature is Th = 341 K</span>
6 0
3 years ago
Increase the slit width to 1050 nm. What happens to the width of the central bright fringe? (Always remember to wait a few secon
djyliett [7]

Answer:

b.

Explanation:

In case of Single Slit, diffraction will occur.

Then In Single slit Diffraction, width of central fringe is

x_c= 2D\lambda/a&#10;

where D= distance b/w screen and slit

a= slit width

\lambda = wavelength

Thus if Screen width increases keeping other factors same then width of central fringe becomes narrower as

x_c\propto 1/a

On increasing the slit width the central bright fringe width The width of the central bright fringe becomes narrower.

3 0
4 years ago
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