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EleoNora [17]
4 years ago
11

it takes a hose 4 minutes to fill a rectangular aquarium 9 inches long, 13 inces wide, and 14 inces tall. how long will it take

the same hose to fill an aquarium measuring 21 inces by 25 inces by 34 inces?
Physics
1 answer:
Studentka2010 [4]4 years ago
4 0

Answer: 43.58 min

Explanation:

Knowing the volume of a rectangular object is length x width x height, we have two volumes:

V_{1}=(9 in)(13 in)(14 in)=1638 in^{3}

V_{2}=(21 in)(25 in)(34 in)=17850 in^{3}

And we know it takes a time of 4 minutes to fill V_{1}.

If we want to know how long will it take the same hose to fill another tank with volume V_{2}, we can use the <u>Rule of three</u>, which is a mathematical rule to find out an amount that is with another quantity given in the same relation as other two also known:

1638in^{3} ---- 4min

17850in^{3} ---- ?

?=\frac{(17850 in^{3})(4min)}{1638 in^{3}}

Finally:

?=43.58 min

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A rotating merry-go-round makes one complete revolution in 4.0s a) what is the linear speed of a child seated 1.2 meters from th
lianna [129]

Answer:a) The linear speed of the rotating merry-go-round is 1.884 m/s.

b) The acceleration of the rotating merry-go-round  device is 2.95m/s^2.

Explanation:

a) linear speed of the device:

Distance =2\pi (r)

Child seated 1.2 meters from the center, which means that radius ,r = 1.2 meters

Time taken to complete one revolution = 4.0 seconds

\text{Linear speed}=v=\frac{distance}{time}=\frac{2\pi r}{t}=\frac{2\times 3.14\times 1.2 m}{4.0 s}=\frac{7.536 m}{4.0 s}=1.884 m/s

The linear speed of the rotating merry-go-round is 1.884 m/s.

b) Acceleration

Linear velocity ,v = 1.884 m/s

a_c=\frac{v^2}{r}

=\frac{1.884 m/s\times 1.884m/s}{1.2 m}=2.95m/s^2

The acceleration of the rotating merry-go-round  device is 2.95m/s^2.

7 0
4 years ago
A space rocket is launched and accelerates uniformly to 160 m/s in 4.5 s. Calculate the acceleration of the rocket.​
-BARSIC- [3]

Answer:

<h2>35.56 m/s²</h2>

Explanation:

The acceleration of an object given it's velocity and time taken can be found by using the formula

a =  \frac{v}{t}  \\

v is the velocity

t is the time

From the question we have

a =  \frac{160}{4.5}  = 35.55555...

We have the final answer as

<h3>35.56 m/s²</h3>

Hope this helps you

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3 years ago
. Which is the transfer of energy as waves moving through space?
Solnce55 [7]

Answer:

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