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Sav [38]
2 years ago
15

A space rocket is launched and accelerates uniformly to 160 m/s in 4.5 s. Calculate the acceleration of the rocket.​

Physics
1 answer:
-BARSIC- [3]2 years ago
6 0

Answer:

<h2>35.56 m/s²</h2>

Explanation:

The acceleration of an object given it's velocity and time taken can be found by using the formula

a =  \frac{v}{t}  \\

v is the velocity

t is the time

From the question we have

a =  \frac{160}{4.5}  = 35.55555...

We have the final answer as

<h3>35.56 m/s²</h3>

Hope this helps you

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A sound wave travels in a straight line at a constant speed of 660 mph. What is
Fed [463]

Answer:

a = 0

Explanation:

The velocity of a sound wave in a straight line is 660 mph. The wave is moving with a constant velocity. It means that the change in velocity is equal to 0.

We know that acceleration of an object is equal to the change in velocity divided by time taken. But here the change in velocity is 0. As a result the acceleration of the sound wave is 0.

8 0
3 years ago
What is the shape of a projectile
Cerrena [4.2K]
The answer I found was parabola?
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3 years ago
1) Arrange the following spectral regions in order of increasing energy: infrared, microwave, ultraviolet, visible.
Anton [14]

Answer:

The order of increasing energy is as follows

"microwave < infrared < visible < ultraviolet"

Option (A) is correct.

Explanation:

Given:

Arrange the following spectral regions in order of increasing energy: infrared, microwave, ultraviolet, visible.

From the formula of energy in terms of frequency.

  E = hf

Where h = planck constant, f = frequency of light.

From above formula we can conclude that higher frequency means higher energy.

In our case ultraviolet has higher frequency and microwave has lower frequency.

So ultraviolet has higher energy and microwave has lower energy.

microwave < infrared < visible < ultraviolet

Therefore, the order of increasing energy is as follows

"microwave < infrared < visible < ultraviolet"

7 0
3 years ago
An orbiting satellite can become charged by the photoelectric effect when sunlight ejects electrons from its outer surface. Sate
Rufina [12.5K]

Answer:

the longest wavelength of incident sunlight that can eject an electron from the platinum is 233 nm

Explanation:

Given data

Φ = 5.32 eV

to find out

the longest wavelength

solution

we know that

hf = k(maximum) +Ф   ...............1

here we consider k(maximum ) will be zero because photon wavelength max when low photon energy

so hf = 0

and hc/ λ = +Ф

so λ = hc/Ф  ................2

now put value hc = 1240 ev nm and Φ = 5.32 eV

so hc = 1240 / 5.32

hc = 233 nm

the longest wavelength of incident sunlight that can eject an electron from the platinum is 233 nm

8 0
3 years ago
A 6.00 cm tall light bulb is placed a distance of 54.2 cm from a double convex lens
BigorU [14]

Answer:

1 / f = 1 / i + 1 / o       thin lens equation

1 / i = 1 / f - 1 / o    =    (o - f) / (o * f)

i = o * f / (o - f)

i = 54.2 * 12.7 / (54.2 - 12.7) = 16.6 cm    image distance

Image is real and inverted and 16.6 / 54.2 * 6 = 1.94 cm tall

7 0
3 years ago
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