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Scrat [10]
1 year ago
5

In many species, a transition metal has an unusually high or low oxidation state. Write balanced equations for the following and

find the oxidation state of the transition metal in the product:(f) Bubbling CO through a basic solution of cobalt(II) ion produces [Co(CO)₄]⁻, CO₃²⁻, and water.
Chemistry
1 answer:
dedylja [7]1 year ago
7 0

When `CO_(2)` is bubbled through a cold pasty solution of barium peroxide in water, `H_(2)O_(2)` is obtained. <br> `BaO+CO_(2)+H_(2)OtoBaCO_(3)+H_(2)O_(2)` Barium carbonate being insoluble is filtered off. This is known as Merck's process.

<h3>What is meant by Perhydrol?</h3>

perhydrol (countable and uncountable, plural perhydrols) A stabilised solution of hydrogen peroxide.

<h3>What is Merck's Perhydrol?</h3>

Uses: Perhydrol is used as an antiseptic for wounds, and also acts as a germicide to kill bacteria and germs.

Being a strong oxidizing agent it has bleaching properties and acts as a ripening agent.

Learn more about merck's process here:

<h3>brainly.com/question/16856280</h3><h3 /><h3>#SPJ4</h3>

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<u>Answer:</u> The number of OH^- ions dissociated are 8.57\times 10^{11}

<u>Explanation:</u>

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2.07+pOH=14\\\\pOH=14-2.07=11.93

To calculate hydroxide ion concentration, we use the equation to calculate pOH of the solution, which is:

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To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Molarity of solution = 1.17\times 10^{-12}M

Volume of solution = 1243 mL = 1.243 L  (Conversion factor: 1 L = 1000 mL)

Putting values in above equation, we get:

1.17\times 10^{-12}M=\frac{\text{Moles of }OH^-}{1.243L}\\\\\text{Moles of }OH^-=(1.17\times 10^{-12}mol/L\times 1.243L)=1.424\times 10^{-12}mol

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1 mole of a compound contains 6.022\times 10^{23} number of particles

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Hence, the number of OH^- ions dissociated are 8.57\times 10^{11}

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