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3 years ago

I need help with these 4

Chemistry

1 answer:

storchak [24]3 years ago

5 0

Rift Valley Examples

East African
Rhine Rift Valley (Germany)
Baikal Rift Valley (Russia)

Rift Valley Facts/Characteristics

Bordered by fault zones and separating land masses
A portion of land that drops, forming a valley.
Formed as tectonic plates move.

Fossils - Examples

Bones
Shells
Exoskeletons
Stone imprints of animals.

Non Examples of Fossils

Stones
rocks
Some bones (If they are fossils they will be a lot heavier than other bones.

Hope this helps.

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Solve the following problem and round the correct number of significant

RUDIKE [14]

Answer:

4.5 + 2.34 = 6.8

Sig Figs:

Decimals:

Scientific Notation:

6.8 × 10ⁿ

Words:

six point eight

5 0

3 years ago

What is the mass of 3.77mol of K3N?

AleksAgata [21]

<h3>Answer:</h3>

495 g K₃N

<h3>General Formulas and Concepts:</h3>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.77 mol K₃N

<u>Step 2: Identify Conversions</u>

Molar Mass of K - 39.10 g/mol

Molar Mass of N - 14.01 g/mol

Molar Mass of K₃N - 3(39.10) + 14.01 = 131.31 g/mol

<u>Step 3: Convert</u>

Set up: $\displaystyle 3.77 \ mol \ K_3N(\frac{131.31 \ g \ K_3N}{1 \ mol \ K_3N})$
Multiply/Divide: $\displaystyle 495.039 \ g \ K_3N$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

495.039 g K₃N ≈ 495 g K₃N

5 0

3 years ago

Photosynthesis takes place in the

guajiro [1.7K]

Answer:

Chloroplast

Explanation:

4 0

3 years ago

PLEASE HELP!!!! <br><br> Draw a representation of John Dalton’s atomic model.

larisa [96]

Answer:

John Dalton's Atomic Model Below ⬇

Explanation:

7 0

2 years ago

Part A of the lab involved adding 4 mL increments of distilled water to 5.00 mL of antimony trichloride solution. The antimony t

Mrrafil [7]

Answer:

0.0238M SbCl3, 1.07M H+, 1.14M Cl-

Explanation:

The total volume of the solution is:

4mL + 5.00mL + 12.0mL = 21mL

As the volume of the SbCl3 is 5.00mL, the dilution factor is:

21mL / 5.00mL = 4.2 times

The concentration of SbCl3 is:

0.10M SbCl3 / 4.2 times = 0.0238M SbCl3

The concentration of H+ = [HCl]:

4.5M / 4.2 times = 1.07M H+

The initial concentration of Cl- is:

3 times SbCl3 + HCl = 0.10M*3 + 4.5M =

<em>3 times SbCl3 because 1 mole of SbCl3 contains 3 moles of Cl-</em>

4.8M Cl- / 4.2 times = 1.14M Cl-

3 0

3 years ago