Answer:
The mass of G1 at all times during this trial was <u>0.5</u> kg.
The velocity of G1 + G2 after the collision was <u>-1.24</u> m/s.
The momentum of G1 after the collision was <u>-2.10</u> kg · m/s.
Explanation:
i got it right
Answer:
Check the explanation
Explanation:
Their is no data provided for the mass and length of pendulum in the picture.but it is very easy to check kinetic energy.KE is mv^2/2, m is the pendulum Bob and v is time dependent ,equation of displacement of SHM is given as x(t)=Asin(wt+∆) where ∆ is the phase angle now v=dX/dt _v=Awcos(wt+∆) and KE=
Thus w angular frequency of oscillation is√(g/l)
g acceleration due to gravity and l length of pendulum.so KE is same for pendulum having same mass and length otherwise KE expression with time will vary for all other cases.now check if all experiment pendulum have same mass and length otherwise KE will not be same.You can now easily verify.
The voltage across all the resistors is the same i.e 120V
Each element of the parallel circuit has the same voltage applied to it. The total current flowing from the source is equal to the sum of the currents across each path. The electric potential difference (V) across each resistor in a parallel circuit is the same. Ohm's law states that I = V / R applies to the current in a resistor. The current will be lowest where the resistance is highest since the V is the same for each resistor. The currents passing through each resistor in a parallel combination have the same voltage across them because of their different resistance values and the laws of Ohms i., If two or more components are connected in parallel, they will be having same difference of potential (voltage) across their ends Parallel circuits are then used as current dividers.
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Answer:
Part a)

Part b)

Part c)

Part d)

Part e)

Part f)

Explanation:
Part a)
Magnitude of tension force is given as
at 26.9 degree with vertical


Part b)
Net force on Tarzen is given as



Part c)
magnitude of the force is given as



Part d)
Direction of the force is given as



Part e)
Magnitude of the acceleration


tex]a = \frac{384.2}{86.5}[/tex]

Part f)
Direction of acceleration is same as the direction of the force
