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NNADVOKAT [17]
2 years ago
14

A paper is placed in between two books can be quickly pulled out without movinf the books. whuch statement explains this phenome

non
Physics
2 answers:
garri49 [273]2 years ago
8 0

Answer:( D ) The books have a great deal of inertia and do not move easily.

Explanation:

Montano1993 [528]2 years ago
7 0
This is easily explained saying that the frictional force between the books and the paper isn't big enough to produce a displacement in the books. The displacement in the books doesn't happen because the frictional force between the books and the surface they are standing on is bigger than the paper's one.
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The 20 or so minerals that make up most of the rocks of earth's crust are know as what
STALIN [3.7K]
Rock-forming minerals because they formed the earths crust
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3 years ago
Two electrons, each with mass mmm and charge qqq, are released from positions very far from each other. With respect to a certai
lana66690 [7]

The answer & explanation for this question is given in the attachment below.

3 0
3 years ago
What is the acceleration of a car that moves at a steady velocity of 100 km/h for 100 seconds? Explain your answer.
RUDIKE [14]

Answer:

a = 0 m/s²

Explanation:

given,

car moving at steady velocity = 100 Km/h

         1 km/h = 0.278 m/s

      100 Km/h = 27.8 m/s

time of acceleration = 100 s

acceleration is equal to change in velocity per unit time.

 a=\dfrac{dv}{dt}

change in velocity of the car is 27.8 - 27.8 = 0

 a=\dfrac{0}{100}

        a = 0 m/s²

If the car is moving with steady velocity then acceleration of the car is zero.

Hence, the acceleration of the car is equal to a = 0 m/s²

3 0
3 years ago
What type of energy does the horse have because of its motion?
Alekssandra [29.7K]

is the horse running/moving? if so then kinetic i believe

7 0
2 years ago
Someone please help with this
SSSSS [86.1K]

Answer:

<em>The new force is 2/3 of the original force</em>

Explanation:

<u>Coulomb's Law </u>

The electrical force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between the two objects.

Written as a formula:

\displaystyle F=k\frac{q_1q_2}{d^2}

Where:

k=9\cdot 10^9\ N.m^2/c^2

q1, q2 = the objects' charge

d= The distance between the objects

Suppose the first charge is doubled (2q1) and the second charge is one-third of the original charge (q2/3). Now the force is:

\displaystyle F'=k\frac{2q_1*q_2/3}{d^2}

Factoring out 2/3:

\displaystyle F'=\frac{2}{3}k\frac{q_1*q_2}{d^2}

Substituting the original force:

F'=\frac{2}{3}F

The new force is 2/3 of the original force

7 0
2 years ago
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