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3 years ago

Which type of plate boundary or zone would be most likely to lead to above-ground volcanic activity?

Physics

1 answer:

Anna007 [38]3 years ago

6 0

Answer:

Convergent plate boundary

Explanation:

The convergent plate boundary refers to the type of boundary where two plates move towards each other. Due to this type of motion, there forms a subduction zone, where the denser plate subducts below the lighter plate. This zone of subduction is commonly identified by the presence of a deep and narrow V-shaped depression which is commonly known as the oceanic trench.

When the subducting plate enters into the region of the asthenosphere, the rocks melt and mix with the magma. This magma is then pushed upward due to the force exerted by the convection current that forms in the mantle, and further reaches the over-riding plate and eventually give rise to the formation of volcanoes and volcanic/island arcs.

Thus, this type of plate boundary is responsible for the formation of above-ground volcanic activities.

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Which formula is used to find an object's acceleration?

Vika [28.1K]

Answer:

4 option is correct ........

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3 years ago

A ball is thrown directly downward with an initial speed of 8.00 m/s, from a height of 30.0m. After what time interval does it s

aniked [119]

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-(9.8/2)t^2-8t+30=0
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3 years ago

An electron is released from rest at a distance of 0.470 m from a large insulating sheet of charge that has uniform surface char

ArbitrLikvidat [17]

Answer:

Part a)

$W = 1.58 \times 10^{-20} J$

Part b)

$v = 1.86 \times 10^5 m/s$

Explanation:

Part a)

Electric field due to large sheet is given as

$E = \frac{\sigma}{2\epsilon_0}$

$\sigma = 4.00 \times 10^{-12} C/m^2$

now the electric field is given as

$E = \frac{4.00 \times 10^{-12}}{2(8.85 \times 10^{-12})}$

$E = 0.225 N/C$

Now acceleration of an electron due to this electric field is given as

$a = \frac{eE}{m}$

$a = \frac{(1.6 \times 10^{-19})(0.225)}{9.1 \times 10^{-31}}$

$a = 3.97 \times 10^{10}$

Now work done on the electron due to this electric field

$W = F.d$

$d = 0.470 - 0.03$

$d = 0.44 m$

So work done is given as

$W = (ma)(0.44)$

$W = (9.11 \times 10^{-31})(3.97 \times 10^{10})(0.44)$

$W = 1.58 \times 10^{-20} J$

Part b)

Now we know that work done by all forces = change in kinetic energy of the electron

so we will have

$W = \frac{1}{2}mv^2 - 0$

$1.58 \times 10^{-20} = \frac{1}{2}(9.1\times 10^{-31})v^2$

$v = 1.86 \times 10^5 m/s$

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3 years ago

The angular momentum about the center of the planet and the total mechanical energy will be conserved regardless of whether the

ValentinkaMS [17]

Answer:

True

Explanation:

The angular momentum around the center of the planet and the total mechanical energy will be preserved irrespective of whether the object moves from large R to small R. But on the other hand the kinetic energy of the planet will not be conserved because it can change from kinetic energy to potential energy.

Therefore the given statement is True.

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3 years ago

if your vehicle begins to slide or skid in the rear, you should? group of answer choices press the gas pedal and speed up. steer

MariettaO [177]

if your vehicle begins to slide or skid in the rear, you should steer in the direction that the rear is sliding to.

<h3>What should you do if the rear end of the vehicle starts to slide or skid?</h3>

In the case above, a person need to Look as well as steer in the direction that the person want the front of the vehicle to go.

Note that in the case above;

Do stay way from the brake pedal and never apply the brakes.

Steer in the the same direction as the rear of the vehicle that is known to be sliding. This will give room for the vehicle to go straight instead of going sideways.
Then make sure to get ready to steer in the opposite direction if the vehicle is one that begins swerving in the other direction.

Therefore, if your vehicle begins to slide or skid in the rear, you should steer in the direction that the rear is sliding to.

Learn more about slide or skid from

brainly.com/question/2148046

#SPJ1

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1 year ago