The c—c—c bond angle in propane, c3h8, is closest to
2 answers:
Propane has a molecular formula C3H8.
It is of the form CnH2n+2.
where n = number of C atoms. In present case n = 3.
Each carbon atom in propane is sp3 hydribized. Thus, there are 4 hydrid orbital associated with each carbon atom
The central C atom is sigma bonded to two other carbon atoms and two hydrogen atoms.
Such, sp3 hydridized orbitals are spacial orientated at an angle of
, in order to minimize repulsion between the electrons.
Hence, the c—c—c bond angle in propane, c3h8, is closest to
It is of the form CnH2n+2.
where n = number of C atoms. In present case n = 3.
Each carbon atom in propane is sp3 hydribized. Thus, there are 4 hydrid orbital associated with each carbon atom
The central C atom is sigma bonded to two other carbon atoms and two hydrogen atoms.
Such, sp3 hydridized orbitals are spacial orientated at an angle of
Hence, the c—c—c bond angle in propane, c3h8, is closest to
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Answer:
a)
b)
c)
Explanation:
Hello,
a) In this case, the given height in cm is:
And the radius in cm is:
Thus, the volume in cubic centimeters which is also equal in mL (1cm³=mL) is:
b) In this case, the given height in mm is:
And the radius in mm is:
Thus, the volume in cubic millimeters is:
c) Finally, since 1000 mL equal 1 L, the required density in g/L turns out:
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