The c—c—c bond angle in propane, c3h8, is closest to
2 answers:
Propane has a molecular formula C3H8.
It is of the form CnH2n+2.
where n = number of C atoms. In present case n = 3.
Each carbon atom in propane is sp3 hydribized. Thus, there are 4 hydrid orbital associated with each carbon atom
The central C atom is sigma bonded to two other carbon atoms and two hydrogen atoms.
Such, sp3 hydridized orbitals are spacial orientated at an angle of
, in order to minimize repulsion between the electrons.
Hence, the c—c—c bond angle in propane, c3h8, is closest to
It is of the form CnH2n+2.
where n = number of C atoms. In present case n = 3.
Each carbon atom in propane is sp3 hydribized. Thus, there are 4 hydrid orbital associated with each carbon atom
The central C atom is sigma bonded to two other carbon atoms and two hydrogen atoms.
Such, sp3 hydridized orbitals are spacial orientated at an angle of
Hence, the c—c—c bond angle in propane, c3h8, is closest to
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Answer:
The partial pressure of CO is 5.54x10⁻⁴⁹atm. You shouldn't worry because it is very low pressure
Explanation:
First, the balanced reaction is:
CO + 1/2O₂ → CO₂
The energies of formation are:
ΔG(CO)=-137.168kJ/mol
ΔG(O₂)=0
ΔG(CO₂)=-394.359kJ/mol
The energy of the reaction is:
The expression for calculate the partial pressure of CO is: