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hoa [83]
2 years ago
12

Two groups of students were tested to compare their speed working math problems. Each group was given the same problems. One gro

up with calculators,the other group without calculators. What is the independent variable,the dependent variable and constant variable?
Chemistry
2 answers:
Vlad [161]2 years ago
8 0

The independent variable is the calculator

The dependent variable is the speed of solving the problem.

The constant variable is the same set of problem that was assigned to two groups of students.  

The dependent variable is the one that is being tested by experimentation. The dependent variable depends on the independent variable.  

The independent variable can b changed by the experimenter whereas the constant variable remains unchanged throughout the experiment.  

jeka57 [31]2 years ago
7 0
The independent variable is the variable being changed. In this case, the independent variable is the calculators. The dependent variable is essentially what you are looking for that <u>depends</u> on the independent variable. In this case it would be time. The constant variable or controlled variable are something that doesn't change and would skew the results. One may be the exact same problem for both groups. Try to come up with two more.
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Be sure to answer all parts. calculate δg ocell for the reaction between cr(s) and cu2+(aq). e ocell = 1.08 j/c. enter your answ
Mademuasel [1]

Answer:

\boxed{-6.29 \times10^{5}\text{ J}}

Explanation:

Step 1. Determine the cell potential

                                                  <u>    E°/V     </u>

2×[Cr ⟶ Cr³⁺ + 3e⁻]                  0.744  V

<u>3×[Cu²⁺ + 2e⁻ ⟶ Cu]             </u>   <u>0.3419 V </u>

2Cr + 3Cu²⁺ ⟶ 3Cu  + 2Cr³⁺    1.086  V

Step 2. Calculate ΔG°

\Delta G^{\circ} = -nFE_{\text{cell}}^{^{\circ}} = -6 \times 96 485 \times 1.086 = \text{-629 000 J}\\\\= \boxed{-6.29 \times10^{5}\text{ J}}

6 0
2 years ago
(Upvote) Two atoms that are isotopes of one another must have the same number of what? A. Electrons B. All Particles C. Protons
UNO [17]
Protons, the number of protons cannot change or the element will change as well.
4 0
3 years ago
What is the molar mass of Al2(SO4)3​
umka21 [38]

Answer:

The molar mass of Al_2(SO_4)_3​ is 342.145 g/mol

Explanation:

The molar mass  is stated as the “mass per unit amount of substance”of a given chemical compound  

Al_2(SO_4)_3​  is Aluminium sulphate. They easily dissolve in water. It is primarily  used as a 'coagulating agent' in the drinking water purification and also in waste and sewage water treatment plants,  

We know,

Atomic weight of Aluminium =  26.981

Atomic weight of Sulphur= 32.065

Atomic weight of  Oxygen =  15.9994

Now molar mass of  Al_2(SO_4)_3​ (Aluminium sulphate) is

=>2(26.981)+3(32.065+4(15.999))

=>53.962 +3(32.065+63.996)

=>53.962+3(96.061)

=>53.962+288.183

=>342.145

4 0
3 years ago
If 50.0 g of formic acid (hcho2, ka = 1.8 x 10^-4) and 30.0 g of sodium formate (NaCHO2) are dissolved to make 500 ml. of soluti
gizmo_the_mogwai [7]

If 50.0 g of formic acid (HCHO2, ka = 1.8 x 10^-4) and 30.0 g of sodium formate (NaCHO2) are dissolved to make 500 ml. of solution, the ph of this solution is 3.35.

Therefore, option C is the correct option.

Given,

Given mass of sodium formate = 30 g

Given mass of formic acid = 50 g

Volume of sodium formate = 500 ml

Volume of formic acid = 500ml

Molar mass of sodium formate = 68 g

Molar mass of formic acid = 46 g

<h3>To calculate concentration of sodium formate and formic acid</h3>

The ratio of number of moles and the volume of solution is Molar concentration of substance.

Concentration of sodium formate

Cb = 30/(68×500)

= 0.00088m

Concentration of formic acid

Ca = 50/(46×500)

= 0.00217m

Now,

by using Henderson hesselbalch equation,

pH = pKa + log(Cb/Ca)

pKa = -log(1.8 × 10^(-4))

= 3.75

pH = 3.75 + log(0.00088/0.00217)

pH = 3.75 - 0.392

pH = 3.35

Thus, we calculated that the value of pH of solution of formic acid and sodium formate is 3.35.

learn more about pH:

brainly.com/question/13423434

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3 0
1 year ago
The vapor pressure of pure pentane and pure hexane are 425 torr and 151 torr respectively. equal moles of pentane and hexane are
nadezda [96]

The mole fraction of pentane in the vapor is 0.291

Vapour pressure rises with temperature and is a measurement of a substance's propensity to transform into a gaseous or vapour state. The boiling point of a liquid is the temperature at which the pressure exerted by its surroundings equals the vapour pressure present at the liquid's surface.

The number of moles of a particular component in the solution divided by the overall number of moles in the sample solution is known as the mole fraction.

Using the formula for vapour pressure,

vapour pressure = P^{}°_{hex} × X_{hex} + P^{}°_{pen} × X_{pen}

vapour pressure = 151 ×  (1-X_{pen}) + 425 × X_{pen}

240 = 151 - 151X_{pen} + 425X_{pen}

240 - 151 = -  151X_{pen} + 425 X_{pen}

89 = 274 X_{pen}

\frac{89}{274} = X_{pen}

0.291 = X_{pen}

Therefore,  the mole fraction of pentane in the vapor is 0.291

Learn more about vapour pressure here;

brainly.com/question/25699778

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3 0
1 year ago
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