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hoa [83]
3 years ago
12

Two groups of students were tested to compare their speed working math problems. Each group was given the same problems. One gro

up with calculators,the other group without calculators. What is the independent variable,the dependent variable and constant variable?
Chemistry
2 answers:
Vlad [161]3 years ago
8 0

The independent variable is the calculator

The dependent variable is the speed of solving the problem.

The constant variable is the same set of problem that was assigned to two groups of students.  

The dependent variable is the one that is being tested by experimentation. The dependent variable depends on the independent variable.  

The independent variable can b changed by the experimenter whereas the constant variable remains unchanged throughout the experiment.  

jeka57 [31]3 years ago
7 0
The independent variable is the variable being changed. In this case, the independent variable is the calculators. The dependent variable is essentially what you are looking for that <u>depends</u> on the independent variable. In this case it would be time. The constant variable or controlled variable are something that doesn't change and would skew the results. One may be the exact same problem for both groups. Try to come up with two more.
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The seawater of Puget Sound off the coast of Oregon has a salinity of about 24 PPT. What weight of salt is there in 1,000g of se
Juli2301 [7.4K]

The given salinity is 24ppt

The relation between salinity and grams is

salinity(ppt)=\frac{gramsofsolute}{massofsolventinkg}

it means there is 24 parts of salt per 1000 parts of water

ppt: parts per thousand

Or

there is 24 grams of salt per 1000g of water

thus the value 24 ppt signifies that there is 24g of salt dissolved in 1000g or 1kg of water

8 0
3 years ago
The majority of elements found in the periodic table can be classified as what
Karo-lina-s [1.5K]
They can be classified as metals.
4 0
2 years ago
Calculate the molality of a 20.0 percent by weight aqueous solution of nh4cl. (molecular weight: nh4cl = 53.5)
cestrela7 [59]
Unfortunately the data provided doesn't include the DENSITY of the ammonium chloride solution and molarity is defined as moles per volume. So without the density, the calculation of the molarity is impossible. But fortunately, there are tables available that do provide the required density and for a 20% solution by weight, the density of the solution is 1.057 g/ml.  
So 1 liter of solution will mass 1057 grams and the mass of ammonium chloride will be 0.2 * 1057 g = 211.4 g. The number of moles will then be 211.4 g / 53.5 g/mol = 3.951401869 mol. Rounding to 3 significant digits gives a molarity of 3.95.  
Now assuming that your teacher wants you to assume that the solution masses 1.00 g/ml, then the mass of ammonium chloride will only be 200g, and that is only (200/53.5) = 3.74 moles.   
So in conclusion, the expected answer is 3.74 M, although the correct answer using missing information is 3.95 M.
8 0
3 years ago
Read 2 more answers
a certain compound was found to contain 54.0 g of carbon and 10.5 grams of hydrogen. its relative molecular mass is 86.0. find t
dexar [7]

Answer:

empirical formula = C3H7

molecular formula = C6H14

3 0
3 years ago
Problem 12.002 the molar analysis of a gas mixture at 30°c, 2 bar is 40% n2, 50% co2, 10% ch4. determine
andreev551 [17]
The problem is incomplete. However, there can only be two probable questions for this problem. First, you can be asked the individual partial pressures of each gas. Second, you can be asked the volume occupied by each gas. I can answer both cases for you.

1.

Let's assume ideal gas.
Pressure for N₂: 2 bar*0.4 = 0.8 bar
Pressure for CO₂: 2 bar*0.5 = 1 bar
Pressure for CH₄: 2 bar*0.1 = 0.2 bar

2. For the volume, let's find the total volume first.

V = nRT/P = (1 mol)(8.314 J/mol-K)(30 +273 K)/(2 bar*10⁵ Pa/1 bar)
V = 0.0126 m³
Hence,
Volume for N₂: 0.0126 bar*0.4 = 0.00504 m³
Volume for CO₂: 0.0126*0.5 = 0.0063 m³
Volume for CH₄: 0.0126*0.1 = 0.00126 m³
3 0
3 years ago
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