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lyudmila [28]
3 years ago
5

Ionic bonds are formed between metal and nonmetal elements. Potassium has only one valence electron and it is stripped away in t

he process of forming an ionic bond. Nonmetals, such as chlorine, tend to gain valence electrons in the formation of ionic bonds. Determine which element(s) are likely to have their electrons stripped away in the formation of ionic bonds. I) aluminum II) sulfur III) oxygen IV) silver V) neon
Chemistry
2 answers:
lisabon 2012 [21]3 years ago
6 0

Answer:

The answer is alimunum and silver.

Explanation:

An ionic bond is produced between metallic and non-metallic atoms, where electrons are completely transferred from one atom to another. During this process, one atom loses electrons and another one gains them, forming ions. Usually, the metal gives up its electrons forming a cation to the nonmetal element, which forms an anion.

As mentioned, metallic elements are those that tend to give up electrons, which bind with atoms that have the ease of accepting them, which are non-metallic elements. Then, <u><em>aluminum and silver, being metals, are the most likely elements to eliminate their electrons in the formation of ionic bonds. </em></u>

Sulfur, oxygen, being nonmetals, will tend to accept electrons. Neon is a noble gas, also called inert, and having its last layer of electrons complete, tends not to react with other elements.

Nonamiya [84]3 years ago
4 0
Aluminum and Silver, as they are metals. Metals are more likely to lose valence electrons.
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Iron(II) is available to bond with chloride ion. How many of each type of ion will bond to form an ionic compound?
Evgesh-ka [11]

Answer:

D) 1 iron(II), 2 chloride

Explanation:

Iron II chloride is the compound; FeCl2. It is formed as follows, ionically;

Fe^2+(aq) + 2Cl^-(aq) -----> FeCl2

The formation of one mole of FeCl2 involves the reaction one mole of iron and two moles of chloride ions. This means that in FeCl2, the ratio of iron to chlorine is 1:2 as seen above.

Therefore there is one iron II ion and two chloride ions in each mole of iron II chloride, hence the answer.

7 0
3 years ago
Is this a correct response? Please help me!
tia_tia [17]
Yes bsjaibsvdnakiebdnsoehdbdnsieveb
4 0
2 years ago
Read 2 more answers
Is a strong acid<br> a. NaC₂H₃O₂ <br> b. HC₂H₃O₂<br> c. KCl <br> d. NH₃<br> e. HCl
sammy [17]
E. HCI

Source:
The Internet
7 0
2 years ago
A mixture of hydrogen and argon gases is maintained in a 6.47 L flask at a pressure of 3.43 atm and a temperature of 85 °C. If t
11Alexandr11 [23.1K]

Answer:

The mixture contains 8.23 g of Ar

Explanation:

Let's solve this with the Ideal Gases Law

Total pressure of a mixture = (Total moles . R . T) / V

We convert T° from °C to K → 85°C + 273 = 358K

3.43 atm = (Moles . 0.082 L.atm/mol.K . 358K) / 6.47L

(3.43 atm . 6.47L) / (0.082 L.atm/mol.K . 358K) = Moles

0.756= Total moles from the mixture

Moles of Ar + Moles of H₂ = 0.756 moles

Moles of Ar + 1.10 g / 2g/mol = 0.756 moles

Moles of Ar = 0.756 moles - 0.55 moles H₂ → 0.206

We convert the moles to g → 0.206 mol . 39.95 g / 1 mol = 8.23 g

8 0
2 years ago
Read 2 more answers
a 1.25g sample of ore containing iron pyrite (FeS2) was pulverized and ignited in air, converting the FeS2 to Fe2O3 and SO2(g).
svp [43]

Answer:

28.9%

Explanation:

Let's consider the following balanced equation.

2 FeS₂ + 11/2 O₂ ⇒ Fe₂O₃ + 4 SO₂

We can establish the following relations:

  • The molar mass of Fe₂O₃ is 159.6 g/mol
  • 1 mole of Fe₂O₃ is produced per 2 moles of FeS₂
  • 1 mole of Fe is in 1 mole of FeS₂
  • The molar mass of Fe is 55.84 g/mol

The amount of Fe in the sample that produced 0.516 g of Fe₂O₃ is:

0.516gFe_{2}O_{3}.\frac{1molFe_{2}O_{3}}{159.6gFe_{2}O_{3}} .\frac{2molFeS_{2}}{1molFe_{2}O_{3}} .\frac{1molFe}{1molFeS_{2}} .\frac{55.84gFe}{1molFe} =0.361gFe

The percent of Fe in 1.25 g of the ore is:

\frac{0.361g}{1.25g} .100\%=28.9\%

4 0
3 years ago
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