The number of moles of oxygen required to generate 28 moles of water from the reaction is 14 moles
<h3>Balanced equation </h3>
2H₂ + O₂ —> 2H₂O
From the balanced equation above,
2 moles of water were obtained from 1 mole of oxygen
<h3>How to determine the mole of oxygen needed </h3>
From the balanced equation above,
2 moles of water were obtained from 1 mole of oxygen
Therefore,
28 moles of water will be obtained from = 28 / 2 = 14 moles of oxygen
Thus, 14 moles of oxygen are needed for the reaction
Learn more about stoichiometry:
brainly.com/question/14735801
Answer:
Explanation:
N and P will have similarity
Electronic configuration of N
2,5
1s²2s²p⁵
Electronic configuration of P
1s²2s²2p⁶3s²3p⁵
Electronic configuration bears similarity.
Both have 5 electrons in their outermost orbits . So they exhibit similarity in their properties. Both belong to the same 15 th group of periodic table.
Sr and Rb too bear much similarity . Both are strongly electro-positive metal , difference in their atomic no being only one.
Answer:
There are 0,89 moles of nitrous oxide gas in the balloon.
Explanation:
We apply the formula of the ideal gases, we clear n (number of moles); we use the ideal gas constant R = 0.082 l atm / K mol:
PV= nRT ---> n= PV/RT
n= 1,09 atm x 20,0 L /0.082 l atm / K mol x 298 K
<em>n= 0,89212637 mol</em>
Answer:
The answer is A
Explanation:
Because the x would be smalle than |-40|
