Shown below is a lewis structure of the formamidinium ion. what geometry is exhibited by the two nitrogens in the formamidinium
ion?
2 answers:
If that is your picture, then the answer is that
Geometry A is trigonal planar
and Geometry B is trigonal pyramidal
Geometry A is trigonal planar
and Geometry B is trigonal pyramidal
The formamidinium ion structure is shown below.
Answer:
A: trigonal planar
B: trigonal pyramidal
Explanation:
In the formamidinium ion, there are two nitrogen atoms, which are represented below by A and B. The geometry of a molecule is determined by the VSEPR theory, which states that the bonded electrons and the lone pairs of electrons intended to repulse to form a more stable compound.
Nitrogen has 5 electrons in its valence shell, so n the nitrogen A, there are 3 bonds (1 double bond and 2 simple bonds), and there are no lone pairs in the nitrogen atom (the central atom), thus the repulsive forces will be only by the bonds, and the geometry will be trigonal planar.
In nitrogen B, there are 3 simple bonds and one lone pair, which contributes to the repulsive forces, thus, the geometry must be trigonal pyramidal.
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Examples of these processes include the reaction of a sodium atom with a chlorine atom to form a sodium cation and a chloride anion; the addition of a hydrogen cation to an ammonia molecule to form an ammonium cation; and the dissociation of a water molecule to form a hydrogen cation and a hydroxide anion.
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