Answer:
a. 1965
b. 8 years
Step-by-step explanation:
For answers to questions like these it can work to consider the smallest possible dataset.
<h3>Dataset</h3>
For our purpose, consider the 9 years/values to be averaged to be ...
1, 2, 3, 4, 5, 6, 7, 8 ,9
<h3>Observations</h3>
a. The center value of the data set is 5. Its number is 5-1=4 more than the first one.
The first centered value is from the year 1961 +4 = 1965.
b. The 4 values at the beginning, and the 4 values at the end do not have a corresponding "average" value. That is, 4+4 = 8 values in the series are lost with respect to the number of average values.
8 years of values are lost.
Answer:
Therefore Perimeter of Rectangle ABCD is 4 units
Step-by-step explanation:
Given:
ABCD is a Rectangle.
A(-6,-4),
B(-4,-4),
C(-4,-2), and
D (-6,-2).
To Find :
Perimeter of Rectangle = ?
Solution:
Perimeter of Rectangle is given as

Length = AB
Width = BC
Now By Distance Formula we have'

Substituting the values we get


Similarly


Therefore now
Length = AB = 2 unit
Width = BC = 2 unit
Substituting the values in Perimeter we get

Therefore Perimeter of Rectangle ABCD is 4 units
Answer:
Provide the graphs by editing the question and then I will edit the answer. But the equation answer is
.
Step-by-step explanation:
<span>The vertex of the parabola is the highest or lowest point of the graph.
</span><span>y=-4x^2+8x-12 = -4 (x^2 -2x +3)
Lets work with this now: </span>x^2 -2x +3
x^2 -2x +3 -> what is the closeset perfect square?
x^2 -2x +1 = (x-1)^2
So
x^2 -2x +3 = (x-1)^2 +2
Replacing to original
y=-4x^2+8x-12 = -4 (x^2 -2x +3) = -4 ((x-1)^2 +2) = -4 (x-1)^2 - 8
The min or max point is where the squared part = 0
So when x=1 , y= -4*0-8=-8
This will be the max of the parabola as there is - for the highest factor (-4x^2)
The max: x=1, y= -8
Answer:
Step-by-step explanation:
Let us first closely examine the sequence for any mathematical correlation between the terms of sequence.
It is visualized that the series is progressing with addition of increasing even numbers starting with +6 ( +6, +8, +10, +12, +14, +16, +18 …) in the previous term to obtain next terms of the series. This logic continues for entire series.
The given series is:
1 ,7 ,15 ,25 ,37
Starting with first number of the series
1
1 + 6 = 7
7 + 8 = 15
15 + 10 = 25
25 + 12 = 37
37 + 14 = 51
51 + 16 = 67
67 + 18 = 85
The extended series is
1, 7, 15, 25, 37, 51, 67, 85