Shortest side (a) = 58
middle side (b) = 64
longest side (c) = 77
the 3 sides a + b + c = 199
b = a + 6
c = a + 19
substitute your new values for b & c into your original formula, so:
a + (a+6) + (a+19) = 199
3a + 25 = 199
3a = 174
a = 58
then substitute 58 into your b & c formulas to figure out the rest
b = a + 6 = 58 + 6 = 64
c = a + 19 = 58 + 19 = 77
Answer:
183.92 inch²
Step-by-step explanation:
To find the total amount of wrapping paper needed, you must find the Surface Area of the box.
Surface area of a rectangular prism is: A = 2(<em>wl</em> + <em>hl</em> + <em>hw</em>)
w = width = 3.8
h = height = 9.5
l = length = 4.2
Plug in the corresponding numbers to the corresponding variables.
A = 2(<em>wl</em> + <em>hl </em>+ <em>hw</em>)
A = 2((3.8 * 4.2) + (9.5 * 4.2) + (9.5 * 3.8))
Simplify.
A = 2((15.96) + (39.9) + (36.1))
A = 2(15.96 + 39.9 + 36.1)
A = 2(91.96)
Multiply.
A = 183.92
183.92 inch² is your answer.
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Answer:
Step-by-step explanation:
(x⁴+ax²+b) ÷ (x+1) = x³-x²+(a+1)x-(a+1) remainder b+(a+1)
Since x+1 is a factor, b+(a+1) = 0.
(x³-x²+(a+1)x-(a+1)) ÷ (x+2) = x²-3x+(a+7) remainder -3a-15
Since x+2 is a factor, -3a-15 = 0
a = -5
b = 4
x⁴+ax²+b = x⁴ - 5x² + 4 = (x²-4)(x²-1) = (x+2)(x-2)(x+1)(x-1)
