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3 years ago

What is 100×23+34-97=___-34+23

Mathematics

1 answer:

AveGali [126]3 years ago

6 0

Answer:

2,180

Step-by-step explanation:

First, you take the left side and solve for it. which if you put 100x23+34-97 it should equal 2,237. Then you take the right side and add it since those are the numers you are given and there is no other option than to add. So it would be 34+23 which shoukd give you 57. Lastly, you take the first answer you got and subtract it from 57. 2,237- 57 and that should give you your answer, 2,180,

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NARA [144]

Answer:

percentage of professional professor are 75

Step-by-step explanation:

Given data

academic professors A = 60%

professors tenured P = 70%

professors at Paracelsus University = 90%

to find out

what percent of the professional professors

solution

we know 90% of the professors are academic professors or tenured or both so we can say percent of academic professors = 60 + 70 - 90 = 40

because here

total = A + P - both

90 = 60 + 70 - both

both = 40

so professors tenured will be here 70 - 40 = 30

percentage of professional professor are = 30 / 40 × 100

percentage of professional professor are 75

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Answer:

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3 years ago

construct a 90% confidence interval of the population proportion using the giver information x=74 n=150

FrozenT [24]

Answer:

The 90% confidence interval of the population proportion is (0.43, 0.56).

Step-by-step explanation:

The (1 - α)% confidence interval for population proportion p is:

$CI=\hat p\pm z_{\alpha/2}\ \sqrt{\frac{\hat p(1-\hat p)}{n}}$

The information provided is:

X = 74

n = 150

Confidence level = 90%

Compute the value of sample proportion as follows:

$\hat p=\frac{X}{n}=\frac{74}{150}=0.493$

Compute the critical value of z for 90% confidence level as follows:

$z_{\alpha/2}=z_{0.10/2}=z_{0.05}=1.645$

*Use a z-table.

Compute the 90% confidence interval of the population proportion as follows:

$CI=\hat p\pm z_{\alpha/2}\ \sqrt{\frac{\hat p(1-\hat p)}{n}}$

$=0.493\pm 1.645\times \sqrt{\frac{0.493(1-0.493)}{150}}\\\\=0.493\pm 0.0672\\\\=(0.4258,\ 0.5602)\\\\\approx (0.43,\ 0.56)$

Thus, the 90% confidence interval of the population proportion is (0.43, 0.56).

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3 years ago

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Alecsey [184]

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