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3 years ago

If a coin is flipped 20 times and a head comes up 7 times, what is the relative frequency of a head coming up?

2 answers:

7 0

Relative frequency is the absolute frequency (i.e. the number of times of the wanted result) divided by the total number of events.

In this case you have to calculate: the number of heads that came up divided by the number of times the coin was flipped.

Number of times the coin was flipped: 20
Numbef of times head came up: 7

Relative frequency: 7 / 20 = 0.35, which is the option B.

sasho [114]3 years ago

3 0

Answer:

0.35

Step-by-step explanation:

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ruslelena [56]

Answer:

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Step-by-step explanation:

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3 years ago

Evaluate u^2 -2u+4 when u= -3

OLga [1]

Answer:

Step-by-step explanation: Sub -3 into where all the u’s are. So it would be

(-3)^2 - 2(-3) + 4

Which would equal 19

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3 years ago

Ms. Moran has started an investment club at BSS. $8000 is invested, some at 10%

labwork [276]

The answer can be readily calculated using a single variable, x:

Let x = the amount being invested at an annual rate of 10%
Let (8000 - x) = the amount being invested at an annual rate of 12%

The problem is then stated as:

(x * 0.10) + ((8000 - x) * 0.12) = 900
0.10(x) + ((8000 * 0.12) - 0.12(x)) = 900
0.10(x) + 960 - 0.12(x) = 900
0.10(x) - 0.12(x) = 900 - 960
-0.02(x) = -60
-0.02(x) * -100/2 = -60 * -100/2
x = 6000 / 2
x = 3000

Thus, $3,000 is invested at 10% = $300 annually; and $8,000 - $3,000 = $5,000 invested at 12% = $600 annually, which sum to $900 annual investment.

6 0

3 years ago

You find an interest rate of 10% compounded quarterly. Calculate how much more money you would have in your pocket if you had us

Elena-2011 [213]

Answer:

see the explanation

Step-by-step explanation:

we know that

step 1

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$r=10\%=10/100=0.10\\n=4$

substitute in the formula above

$A=P(1+\frac{0.10}{4})^{4t}$

$A=P(1.025)^{4t}$

Applying property of exponents

$A=P[(1.025)^{4}]^{t}$

$A=P(1.1038)^{t}$

step 2

The formula to calculate continuously compounded interest is equal to

$A=P(e)^{rt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

e is the mathematical constant number

we have

$r=10\%=10/100=0.10$

substitute in the formula above

$A=P(e)^{0.10t}$

Applying property of exponents

$A=P[(e)^{0.10}]^{t}$

$A=P(1.1052)^{t}$

step 3

Compare the final amount

$P(1.1052)^{t} > P(1.1038)^{t}$

therefore

Find the difference

$P(1.1052)^{t} - P(1.1038)^{t}$ ----> Additional amount of money you would have in your pocket if you had used a continuously compounded account with the same interest rate and the same principal.

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3 years ago

Please help I need to get school work done before 3

Leno4ka [110]

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3 years ago