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andrew-mc [135]
3 years ago
6

Each degree on the Kelvin scale equals:

Chemistry
2 answers:
borishaifa [10]3 years ago
8 0
A change of 1 Kelvin is exactly the same as a change of 1 degree Celsius.
rjkz [21]3 years ago
3 0

Answer is: 1°C.

A change of 1 Kelvin is the same as a change of 1 degree Celsius.

The temperature T in degrees Celsius (°C) is equal to the temperature T in Kelvin (K) minus 273,15: T(°C) = T(K) - 273.15.

For example:

T(He) = 4,2 K.

T(He) = 4,2 K - 273,15.

T(He) = -268,95°C.

The Celsius scale was based on 0°C for the freezing point of water and 100°C for the boiling point of water at 1 atm pressure.


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Answer:

Protons and Neutrons are found in the nucleus

7 0
3 years ago
What is the percent composition of aluminum in the ore bauxite (AI2O3)?
Schach [20]

Answer:

Molar mass of Al2O3 = 101.961276 g/mol

This compound is also known as Aluminium Oxide.

Convert grams Al2O3 to moles or moles Al2O3 to grams

Molecular weight calculation:

26.981538*2 + 15.9994*3

Percent composition by element

Element Symbol Atomic Mass # of Atoms Mass Percent

Aluminium Al 26.981538 2 52.925%

Oxygen O 15.9994 3 47.075%

Explanation:

Percent composition by element

Element Symbol Mass Percent

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Oxygen O 47.075%

6 0
2 years ago
When 70.4 g of benzamide (C7H7NO) are dissolved in 850. g of a certain mystery liquid X, the freezing point of the solution is 2
Arlecino [84]

Answer:

1.62

Explanation:

From the given information:

number of moles of benzamide  =\dfrac{70.4 \ g}{121.14 \ g/mol}

= 0.58 mole

The molality = \dfrac{mass \ of \ solute (i.e. \ benzamide )}{mass \ of \ solvent  }

= \dfrac{0.58 }{0.85 }

= 0.6837

Using the formula:

\mathbf {dT  = l   \times  k_f  \times m}

where;

dT = freezing point = 27

l = Van't Hoff factor = 1

kf = freezing constant of the solvent

∴

2.7 °C = 1 × kf ×  0.6837 m

kf = 2.7 °C/ 0.6837m

kf = 3.949 °C/m

number of moles of NH4Cl = \dfrac{70.4 \ g}{53.491 \  g /mol}

= 1.316 mol

The molality = \dfrac{1.316 \ mol}{0.85 \ kg}

= 1.5484

Thus;

the above kf value is used in determining the  Van't Hoff factor for  NH4Cl

i.e.

9.9 = l × 3.949 × 1.5484 m

l = \dfrac{9.9}{3.949 \times 1.5484 \ m}

l = 1.62

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What properties are attributed to a solid with the type of bonding represented in the picture?
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B it is a cold melting point
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AVprozaik [17]

Answer:

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