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3 years ago

PLEASE HELP!!!

Chemistry

1 answer:

sergij07 [2.7K]3 years ago

4 0

oxygen, hydrogen, sulfur, iodine, iron, carbon, nitrogen, phosphorus, calcium.

are the answers

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A sample of 10.5 g of nitrogen reacts with 20.2 g of hydrogen to produce ammonia. (36 points

BartSMP [9]

Answer:

Explanation:

A. 55

B. 43

C. 14

D. 29

6 0

1 year ago

26 g of zinc combines with 12.8 g of sulfur. What is the empirical formula of zinc sulfide?

Alisiya [41]

Moles of Zn: 26 / 65 = 0.4
Moles of S: 12.8 / 32 = 0.4

Molar ratio of Zn : S = 1 : 1
Empircal formula: ZnS

The answer is C

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3 years ago

NEEED HELP PLEASE IM VERY STRESSED

Arte-miy333 [17]

Answer:

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Explanation:

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2 years ago

Why does potassium explode when exposed to water?

soldi70 [24.7K]

Answer:

The highly unstable pure sodium or potassium wants to lose an electron and this splits the water atom, producing a negatively charged hydroxide ion and hydrogen and forming an explosive gas that ignites.

Explanation:

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2 years ago

Which ionic equation describes a redox reaction? A. Ag(+) + Cl- = AgCl B. 2H(+) + CO3(2-) = CO2 + H2O C. H(+) + OH(-) = H2O D. Z

Gennadij [26K]

Answer: The correct option is D. $Zn+Cu^{2+}\rightarrow Zn^{2+}+Cu$

Explanation:

Redox reaction is defined as the reaction in which oxidation and reduction take place simultaneously. It is known as the reaction in which the exchange of electrons takes place.

The oxidation reaction is defined as the reaction in which a chemical species loses electrons in a chemical reaction. It occurs when the oxidation number of a species increases.

A reduction reaction is defined as the reaction in which a chemical species gains electrons in a chemical reaction. It occurs when the oxidation number of a species decreases.

From the given ionic reactions:

$Zn+Cu^{2+}\rightarrow Zn^{2+}+Cu$

On the reactant side:

Oxidation number of Zn = 0

Oxidation number of Cu = +2

On the product side:

Oxidation number of Cu = 0

Oxidation number of Zn = +2

As the oxidation number of Zn is increasing from 0 to +2. Thus, it is getting oxidized. Similarly, the oxidation number of Cu is decreasing from +2 to 0. Thus, it is getting reduced. Therefore, forming a redox couple

Hence, the correct option is D. $Zn+Cu^{2+}\rightarrow Zn^{2+}+Cu$

6 0

2 years ago