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ki77a [65]
4 years ago
6

PLEASE HELP!!!

Chemistry
1 answer:
sergij07 [2.7K]4 years ago
4 0

oxygen, hydrogen, sulfur, iodine, iron, carbon, nitrogen, phosphorus, calcium.

are the answers

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If there are the same number of argon atoms in one sample and the same number of carbon atoms in another, then the value of the
Art [367]

Answer:

c. 0.30

Explanation:

One C atom has a mass of 12.0 u and one Ar atom has a mass of 40.0 u.

Let’s assume that there are <em>n</em> atoms of C and <em>n</em> atoms of Ar. Then

Mass of <em>n</em> C atoms = <em>n</em> × 12.0

Mass of <em>n</em> C atoms = 12.0<em>n</em> u

Mass of <em>n</em> Ar atoms = <em>n</em> × 40.0

Mass of <em>n</em> Ar atoms = 40.0<em>n</em> u

ratio = mass of C/mass of Ar

ratio = 12.0<em>n</em>/40.0<em>n </em>

ratio = 0.300

8 0
3 years ago
A gas storage cylinder in an ordinary chemical laboratory measures 6.6cm wide and 26.Cm high. This is the label on it. N2 gas Pr
Stels [109]

Answer:The final volume of nitrogen gas will be 13 L. Nitrogen gas was collected in the plastic bag.

Explanation:

Volume of the storage cylinder:

Volume of the cylinder = \pi r^2h

Diameter of the cylinder (d)= 6.6 cm

So, radius of the cylinder =\frac{d}{2}=\frac{6.6}{2}=3.3cm

Height of the cylinder = 26 cm

Volume of the cylinder==V_1=\pi r^2h=3.14\times (3.3cm)^2\times 26cm=889.05 cm^3=889.05\times 10{-3} L(1cm^3=10^{-3}L)

Pressure of the N_2 gas in a cylinder =P_1= 14.9 atm

The cylinder is opened and the gas allowed to escape into a large empty plastic bag. So, now the value of the pressureP_2 will become equal to atmospheric pressure that 1 atm .

Volume of N_2 gas in plastic bag V_2 will be given by the expression of Boyle's law

P_1V_1=P_2V_2

On substituting the values:

14.9\times 889.05\times 10^{-3} L= 1atm \times V_2=

V_2=13.24 L

The final volume of nitrogen gas will be 13.24 L when rounded of to two significant figures will be 13 L. Nitrogen gas was collected in the plastic bag.

5 0
3 years ago
15Q= 1s2 2s2 2p6 3s2 3p3<br> 18T=<br> 23A=<br> 6X=<br> 3G=<br> 31L=<br> 84D=<br> 12M=
luda_lava [24]

Answer:

what grade are you in

Explanation:

5 0
4 years ago
Pretty ez im just dum, extra points!!!!!!!
nika2105 [10]

Answer:

As a compound maybe, I'm not quite sure.

sorry and good luck.

8 0
3 years ago
0.38 L of HNO3 is titrated to equivalence using 0.14 L of 0.2 MNaOH. What is the concentration of the HNO3HNO3
malfutka [58]

Answer:

0.074M is concentration of the HNO₃ solution

Explanation:

The reaction of neutralization of nitric acid, HNO₃ with NaOH is:

HNO₃ + NaOH → H₂O + NaNO₃

<em>Where 1 mole of nitric acid reacts per mole of NaOH</em>

<em />

Based on the chemical reaction, the moles of NaOH at equivalence point are equal to moles of HNO₃ presents in the solution. With the moles and the volume we can find molarity as follows:

<em>Moles NaOH = Moles HNO₃:</em>

0.14L * (0.2mol NaOH / L) = 0.028mol NaOH  = 0.028mol HNO₃

<em>Molarity:</em>

0.028mol HNO₃ / 0.38L =

<h3>0.074M is concentration of the HNO₃ solution</h3>
3 0
3 years ago
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