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kati45 [8]
4 years ago
5

Transamination removes the amino group to form a carbon skeleton that contains

Chemistry
2 answers:
tangare [24]4 years ago
7 0

Answer:

k

Explanation:

kidfkvyg bt tgk mg RH g fu f

Talja [164]4 years ago
5 0

Answer:

false no oxygen atoms in skeleton system

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If a can of soup 150 g mass and 0.75g/ cm^3 density what’s the volume
Liula [17]

Answer:

<h3>The answer is 200 cm³</h3>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density}\\

From the question

mass = 150 g

density = 0.75 g/cm³

We have

volume =  \frac{150}{0.75}  \\

We have the final answer as

<h3>200 cm³</h3>

Hope this helps you

8 0
4 years ago
A glass flask of volume 400cm is just filled with mercury at 0 degree ​
3241004551 [841]

<em>A glass flask of volume 400 cm³ is just filled with mercury at 0°C. How much mercury will  overflow when the temperature of the system rises to 80°C.​</em>

<em />

The volume of mercury that overflow is 5.376 cm³

<h3>Further explanation</h3>

Given

volume of glass = 400 cm³

Δt=80 °C - 0 °C = 80

Required

overflow volume

Solution

With an increase in the temperature of the substance, objects can expand. This expansion includes volume expansion.

Can be formulated

\tt V_t=V_o(1+\gamma.\Delta t)\\\\\Delta V=V_o.\gamma.\Delta t

Find volume expansion of glass and mercury

  • Glass(γ = 1.2.10⁻⁵ C⁻¹)

\tt \Delta V=400\times 1.2.10^{-5}.80=0.384~cm^3

  • Mercury(γ=1.8.10⁻⁴ C⁻¹)

\tt \Delta V=400\times 1.8.10^{-4}\times 80=5.76~cm^3

Overflow :

ΔV mercury - ΔV glass : 5.76-0.384 = 5.376 cm³

7 0
3 years ago
Make the selection that best completes the sentence.
mylen [45]
The answer would be C. in an ellipse

Hope this answer helps!
5 0
3 years ago
Read 2 more answers
If the half life of a radioactive isotope is 1 day, then how much of the original isotope remains at the end of two days?
ikadub [295]

\huge{\color{magenta}{\fcolorbox{magenta}{black}{\huge{\color{white}{\fcolorbox{aqua}{black}{✿ᴀɴsᴡᴇʀ✿}}}}}}

25%

Explanation:

In a half life of a radioactive isotope is 1 day,it means it loses its half mass each day

We a formula for N half life

\sf  { \frac{1}{2} }^{n}

where n is the number of days

Here the isotope is kept for 2 days

so it's left over mass will be

\sf { (\frac{1}{2}) }^{2}  \\  \\  \\  \frac{1}{2}  \times  \frac{1}{2}  \\  \\  \sf  \frac{1}{4}

It's left over mass 1/4th of the original mass

Now, we need to find it's percentage by multiplying with 100

\sf  \frac{1}{4}  \times 100 \%\\  \\  \sf   \cancel\frac{100}{4} \% \\  \\  \sf 25\%

<u>So</u><u> </u><u>2</u><u>5</u><u>%</u><u> </u><u>mass</u><u> </u><u>will</u><u> </u><u>be</u><u> </u><u>left</u><u> </u><u>after</u><u> </u><u>2</u><u> </u><u>day</u><u> </u><u>of</u><u> </u><u>half</u><u> </u><u>life</u><u> </u><u>radioactive</u><u> </u><u>isotope</u><u>.</u><u> </u>

8 0
2 years ago
Read 2 more answers
An unknown compound is treated at 0o C with bromine in the dark (reaction 1). The predominant product of this reaction is treate
miskamm [114]

Answer:

fgfgfgf

Explanation:v

6 0
3 years ago
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