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3 years ago

A sample of nitrogen occupies 1.00L at a temperature of 250.k. What volume would it occupy at 1500.k?

Chemistry

2 answers:

melamori03 [73]3 years ago

4 0

Answer:

$V_2=6.00L$

Explanation:

Hello,

In this case, Charles' law help us to determine the required volume considering its model equation:

$V_1T_2=V_2T_1$

Whereas the unknown is the volume at the second state:

$V_2=\frac{V_1T_2}{T_1}=\frac{1.00l*1500K}{250K} =6.00L$

One substantiates this results considering that the higher the temperature, the greater the occupied volume by the gas.

Best regards.

11111nata11111 [884]3 years ago

3 0

Your answer to the question is 6.

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Tresset [83]

Answer:

A sample of water boils and releases gas.

Explanation:

Physical change is a change where no any chemical reaction takes place only the chemical composition of matter changes. It is a reversible process .

Burning of newspaper, rusting of iron, plant changes carbon dioxide and water into sugar (photosynthesis) are chemical reaction and irreversible process.

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3 years ago

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Why is there a vast amount of salt water on Earth?

Diano4ka-milaya [45]

Water is an excellent solvent, salt is carried by the water due to erosion and carried to the ocean.

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3 years ago

Two voltaic cells are to be joined so that one will run the other as an electrolytic cell. In the first cell, one half-cell has

vladimir1956 [14]

Au/Cr cell will run as a voltaic cell and Co/Zn cell will run as an electrolytic cell.

<h3>What is an electrolytic cell?</h3>

An electrolytic cell that uses electrical energy to enable a non-spontaneous redox reaction is known as an electrolytic cell.

Certain chemicals can be electrolyzed using electrolytic cells, which are electrochemical cells.

For example, water can be electrolyzed to create gaseous oxygen and gaseous hydrogen with the use of an electrolytic cell.

The following are the three essential parts of electrolytic cells:

Cathode (which is negatively charged for electrolytic cells)

Anode (which is positively charged for electrolytic cells)

Electrolyte

The reactions for each half cell is given by

$Au^{3+}(aq) + 3e^- \rightleftharpoons Au(s)$ ; E° = 1.50 V

$Cr^{3+}(aq) + 3e^- \rightleftharpoons Cr(s)$ ; E° = –0.74 V

$Co^{2+}(aq) + 2e^- \rightleftharpoons Co(s)$ ; E° = –0.28 V

$Zn^{2+}(aq) + 2e^- \rightleftharpoons Zn(s)$ ; E° = –0.76 V

When the Au/Cr cell will run as a voltaic cell and Co/Zn cell will run as an electrolytic cell, the a difference in the voltages is produced

$E^o_{series} = E^o_{Au/Cr} - E^o_{Co/Zn}$ = 2.24 V – 0.48 V = 1.76 V

Learn more about electrolytic cell:

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1 year ago

Assuming constant pressure, rank these reactions from most energy released by the system to most energy absorbed by the system,

givi [52]

Answer: The order from the Most energy released to most Energy Absorbed Is given as 2---> 4--->,3-->---> 1

B)-61.9 kJ

Explanation:

The change in the internal energy of a system is positive if the reaction absorbs energy and negative if the reaction releases energy. For a system to cause an increase in volume, it must have very high energy built up to be released.

1. Surroundings get colder and the system decreases in volume. Here, the surrounding absorbs energy resulting in positive ΔE

2. Surroundings get hotter and the system expands in volume. Here energy is released causing the system to be negative

3. Surroundings get hotter and the system decreases in volume. Although there is a decreased volume, the system is negative because it releases energy

4. Surroundings get hotter and the system does not change in volume. System is negative because it releases energy even thgoygh there is no change in volume

Therefore the order from the Most energy released to most Energy Absorbed Is given as 2---> 4--->,3-->---> 1

b) Using

ΔE = q+ w from 1st law of thermodynamics

ΔE= ΔH - P ΔV

gIven

ΔH = -75.0KJ

volume= A change from 5.0L TO 2.0L = Final volume - initial volume = 2-5= -3.00L

P= 43.0atm

ΔE= ΔH - P ΔV

P ΔV = 43 atm x -3 = -129L.atm

We first convert L-atm to Joules.

1 L-atm = 101.325 Joules.

129L.atm = 129 x 101.325 = - 13071 J

to KJ becomes

13071/1000 = - 13.071KJ

Recall ΔE= ΔH - P ΔV and putting values

ΔE = -75.0 - (-13.071 KJ)= -75.0 kJ + 13.071 kJ = -61.9 kJ

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3 years ago

Determine the oxidation number of the element "J" in H3JO2-

igor_vitrenko [27]

Answer:

Oxidation number:

3*1+ oxidation number of J+2*-2= -1

Oxidation number of J = 0

5 0

2 years ago