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2 years ago

A sample of nitrogen occupies 1.00L at a temperature of 250.k. What volume would it occupy at 1500.k?

Chemistry

2 answers:

melamori03 [73]2 years ago

4 0

Answer:

$V_2=6.00L$

Explanation:

Hello,

In this case, Charles' law help us to determine the required volume considering its model equation:

$V_1T_2=V_2T_1$

Whereas the unknown is the volume at the second state:

$V_2=\frac{V_1T_2}{T_1}=\frac{1.00l*1500K}{250K} =6.00L$

One substantiates this results considering that the higher the temperature, the greater the occupied volume by the gas.

Best regards.

11111nata11111 [884]2 years ago

3 0

Your answer to the question is 6.

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Answer:

For a: The balanced equation is $2S(s)+3O_2(g)\rightarrow 2SO_3(g)$

For c: The balanced equation is $2NaOH(s)+H_2SO_4(aq)\rightarrow Na_2SO_4(aq)+2H_2O(l)$

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A balanced chemical equation is one where all the individual atoms are equal on both sides of the reaction. It follows the law of conservation of mass.

For (a):

The given unbalanced equation follows:

$S(s)+O_2(g)\rightarrow SO_3(g)$

To balance the equation, we must balance the atoms by adding 2 infront of both $S(s)$ and $SO_3$ and 3 in front of $O_2$

For the balanced chemical equation:

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For (b):

The given balanced equation follows:

$2Al(s)+3Cl_2(g)\rightarrow 2AlCl_3(s)$

The given equation is already balanced.

For (c):

The given unbalanced equation follows:

$2NaOH(s)+H_2SO_4(aq)\rightarrow Na_2SO_4(aq)+H_2O(l)$

To balance the equation, we must balance the atoms by adding 2 infront of $H_2O(l)$

For the balanced chemical equation:

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For (d):

The given balanced equation follows:

$C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(g)$

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