Question

What mass of sodium hydroxide will completely neutralize 2.5 mol of sulfuric acid?

Answer 1

Given :

2.5 mole of Sulfuric acid $( H_2SO_4 )$ .

To Find :

Mass of sodium hydroxide will completely neutralize 2.5 mol of sulfuric acid

Solution :

Let us assume volume of water be 1 L .

Now , we know , to neutralize 1 mole of sulfuric acid we need 2 moles of NaOH .

So , for 2.5 mole sulfuric acid required 5 mole of NaOH .

Moles of NaOH ,

$n=M\times Volume \\\\n=5\times 1=5\ moles$  

Molecular mass of NaOH , M.M = 58.44 g/mol .

Mass of 5 moles of NaOH :

$m=5\times 58.44\ g\\\\m=292.2\ g$

Hence , this is the required solution .