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Kisachek [45]
2 years ago
10

What is the resistance of a circuit with a voltage of 10 volts (V) and a current of 5 amps (A)? Use Ohm’s law to calculate the r

esistance.
Physics
2 answers:
iogann1982 [59]2 years ago
5 0

Answer: 2Ω

Explanation:

V = IR

R = V/I

R = 10/5 = 2Ω

Hope it helped!

MAXImum [283]2 years ago
4 0

Answer:

The resistance of a circuit is 2 ohm.

Explanation:

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A roller coaster car rapidly picks up speed as it
TiliK225 [7]
Acceleration = (change of speed) / (time for the change)

Change in speed = (22 - 4) = 18 m/s.
Time for the change = 3 sec.

Acceleration = 18/3 = 6 m/s per second.
8 0
3 years ago
An object has a momentum of 4,000 kg-m/s and a mass of 115 kg. It crashes into another object that has a mass of 100 kg, and the
ANTONII [103]

Answer:

18.60  m/s

Explanation:

Original momentum = mv = 4000        with m = 115    

after collision   m = 115 + 100 = 215 kg

  but the total momentum is still the same (conserved)

          4000 = 215 v      shows v = 18.60 m/s

4 0
2 years ago
This experiment deals with the relationship between volume and temperature for a fixed amount of gas at constant pressure. Desig
creativ13 [48]

Your experiment should keep one thing constant and measure the other. So vary the temp and measure the pressure. You will get a set of data that relates pressure with temp.
<span>PV = nRT
So
P and T are directly proportional.
</span>These experiments are one of either Boyle-Mariottte's, Gay-Lussac'a or Charles' law.

8 0
3 years ago
A thin film of soap with n = 1.34 hanging in the air reflects dominantly red light with λ = 642 nm. What is the minimum thicknes
wariber [46]

Answer:

The minimum thickness of the film and the wavelength of the light in air are 1.197\times10^{-7}\ m and 371 nm.

Explanation:

Given that,

Refractive index of soap= 1.34

Refractive index  of glass= 1.55

Wavelength = 642 nm

(I). We need to calculate the minimum thickness

Using formula of thickness

t=\dfrac{(2m+1)\lambda}{4n}

Where, m = 0 for constrictive

Put the value into the formula

t=\dfrac{(642\times10^{-9})}{4\times1.34}

t=1.197\times10^{-7}\ m

(II). We need to calculate the wavelength

Using formula of wavelength

\lambda=\dfrac{2nt}{m}

Where, m = 1

Put the value into the formula

\lambda=\dfrac{2\times1.55\times1.197\times10^{-7}}{1}

\lambda=371\ nm

Hence, The minimum thickness of the film and the wavelength of the light in air are 1.197\times10^{-7}\ m and 371 nm.

6 0
2 years ago
A 66-kg base runner begins his slide into second base when he is moving at a speed of 3.4 m/s. The coefficient of friction betwe
Helen [10]

Answer:

a ) = 381.48 J

b )=  84.25 cm

Explanation:

Kinetic energy of the runner

= 1/2 m v²

= .5 x 66 x 3.4²

= 381.48 J

The final kinetic energy of the runner is zero .

Loss of mechanical energy

= 381.48 J

This  loss in  mechanical energy is due to action of frictional force .

b )

Let s be the distance of slide

deceleration due to frictional force

= μmg/m

.7 x 66 x 9.8 / 66

a = - 6.86 m s⁻¹

v² = u² - 2 a s

0 = 3.4² - 2x6.86 s

s = 3.4² / 2x6.86

= .8425 m

84.25 cm

5 0
2 years ago
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