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IRISSAK [1]
3 years ago
15

8. The moon has about 1/6th the gravity of the Earth. How would the potential energy of an object be different on the moon if it

was the same height above the ground? (5 pts)
Physics
1 answer:
topjm [15]3 years ago
7 0

The potential energy on the moon would be 1/6 of the potential energy on Earth

Explanation:

The potential energy of an object is the energy possessed by the object due to its position in a gravitational field, and it is given by

PE=mgh

where

m is the mass of the object

g is the strength of the gravitational field

h is the height of the object above the ground

In this problem, the potential energy of the object on the Earth is

PE=mgh

On the Moon, the gravity is

g'=\frac{1}{6}g

Therefore, if the same object (same mass) is placed at the same height h on the Moon, its potential energy would be

PE' = m(\frac{1}{6}g)h = \frac{1}{6}(mgh) = \frac{1}{6}PE'

Learn more about potential energy:

brainly.com/question/1198647

brainly.com/question/10770261

#LearnwithBrainly

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Answer:

F = 2.6692 x 10⁻⁹ N

Explanation:

Given,

The mass of the rock, m = 10 kg

The mass of the boulder, M = 100 kg

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The gravitational force between the two bodies is proportional to the product of their masses and inversely proportional to the square of the distance between them. It is given by the formula

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Substituting the given values,

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Hence, the force between the two bodies is, F = 2.6692 X 10⁻⁹ N

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F2 = 28.5 / 1.53

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