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xz_007 [3.2K]
3 years ago
7

A grandfather clock depends on the period of a pendulum to keep correct time. Suppose a grandfather clock is calibrated correctl

y and then a mischievous child slides the bob of the pendulum downward on the oscillating rod. The grandfather clock will run:
Physics
2 answers:
sweet-ann [11.9K]3 years ago
7 0

The grandfather clock will run: slower

<h3>Explanation: </h3>

A grandfather clock depends on the period of a pendulum to keep correct time. Suppose a grandfather clock is calibrated correctly and then a mischievous child slides the bob of the pendulum downward on the oscillating rod.

A pendulum is a weight that get suspended from a pivot, therefore it can swing freely. A pendulum clock is the clock using a pendulum, a swinging weight, as its timekeeping element.

Calibrate in physics means to ascertain the caliber of and to determine, rectify, or mark the graduations of something, such as a thermometer tube.

A bob is the weight located on the end of a pendulum found in pendulum clocks.

The time period of simple pendulum is given by:

T = 2 \pi \sqrt{\frac{L}{g} }

The time period of a simple pendulum is defined as the time taken by the pendulum to finish one full oscillation.

Where l is the effective length of the pendulum, and g is the acceleration due to gravity

The grandfather clock will run: Slower. Because as the length of the pendulum increase, the tie period of the pendulum also increase.  It means the clock run slow.

Learn more about   pendulum brainly.com/question/8411900

#LearnWithBrainly

Setler [38]3 years ago
6 0

Answer:

Slow

Explanation:

As we know that the time period of simple pendulum is given by

T = 2\pi \sqrt{\frac{L}{g}}

Where, l be the effective length of the pendulum and g be the acceleration due to gravity

As the length of the pendulum increase, then the tie period of the pendulum will also increase.

It means the clock run slow.

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Answer:

0.49m

Explanation:

So you need to change the original equation for finding fields to find distance, and then just plug in the numbers

Which equals 0.49meters

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3 years ago
Dr. John Paul Stapp was U.S. Air Force officer whostudied the effects of extreme deceleration on thehuman body. On December 10,
Ira Lisetskai [31]

Answer:

(a) a = 56.4 m/s², his acceleration a, in multiples of gravity g, is 5.76 g

(b) a = -201.43 m/s², his deceleration -a, in multiples of gravity g, is -20.56 g

Explanation:

(a)

When moving upwards, the initial velocity, u = 0 (he accelerated from rest)

When moving upwards, the final velocity, v = 282 m/s

time of  motion during this acceleration, t = 5 s

His acceleration is calculated as;

v = u + at

282 = 0 + 5a

a = 282 / 5

a = 56.4 m/s²

Ratio of his acceleration, a to gravity, g = a/g = 56.4 / 9.8 = 5.76

a = 5.76 g

(b)

When moving downwards, the initial velocity, u = 282 m/s

When moving downwards, the final velocity, v = 0 (he was brought to rest)

time of  motion during this deceleration, t = 1.4 s

His deceleration is calculated as;

v = u + at

0 = 282 + 1.4a

1.4a = -282

a = -282 / 1.4

a = -201.43 m/s²

Ratio of his deceleration, -a to gravity, g = -a/g = 201.43 / 9.8 = 20.56

a = -20.56 g

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The quadriceps muscles pull on the patella simultaneously. Below are the forces from each
Nostrana [21]

Based on the calculation of the resultant of vector forces:

  1. the resultant force due to the quadriceps is 1795 N
  2. the resultant force due to the quadriceps is 1975 N. Training and strengthening the vastus medialis results in a greater force of muscle contraction.

<h3>What is the resultant force due to the quadriceps?</h3>

The resultant of more than two vector forces is given by:

  • F = √Fₓ² + Fₙ²

where:

  • Fₓ is the sum of the horizontal components of the forces
  • Fₙ is the sum of the vertical components of the forces
  • Fx = F₁cosθ + F₂cosθ + F₃cosθ + F₄cosθ
  • Fₙ = F₁sinθ + F₂sinθ + F₃sinθ + F₄sinθ
  • F₁ = 680N, θ = 90 = 30 = 120°
  • F₂ = 220 N, θ = 90 + 16 = 106°
  • F₃ = 600 N, θ = 90 + 15 = 105°
  • F₄ = 480 N, θ = 90 - 35 = 55°

then:

Fx = 680 * cos 120 + 220 * cos 106 + 600 * cos 105 + 480 * cos 55

Fx = -280.6 N

Fₙ = 680 * sin 120 + 220 * sin 106 + 600 * sin 105 + 480 * sin 55

Fₙ = 1773.1 N

then:

F = √(-280.6)² + ( 1773.1)²

F = 1795.16 N

F ≈ 1795 N

Therefore, the resultant force due to the quadriceps is 1795 N

<h3>What would happen if the vastus medialis was trained and strengthened to contract with 720N of force?</h3>

From the new information provided:

  • F₁ = 680N, θ = 90 = 30 = 120°
  • F₂ = 220 N, θ = 90 + 16 = 106°
  • F₃ = 600 N, θ = 90 + 15 = 105°
  • F₄ = 720 N, θ = 90 - 35 = 55°

then:

Fx = 680 * cos 120 + 220 * cos 106 + 600 * cos 105 + 720 * cos 55

Fx = -142.95 N

Fₙ = 680 * sin 120 + 220 * sin 106 + 600 * sin 105 + 720 * sin 55

Fₙ = 1969.72 N

then:

F = √(-142.95)² + ( 1969.72)²

F = 1974.9 N

F ≈ 1975 N

Therefore, the resultant force due to the quadriceps is 1975 N.

Training and strengthening the vastus medialis results in a greater force of muscle contraction.

Learn more about resultant of forces at: brainly.com/question/25239010

3 0
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