Explanation:
For each point:
PE = mgh
KE = ½ mv²
ME = PE + KE
Since energy is conserved, ME will be constant.
I'll be using g = 10 m/s².
A. PE = (100 kg) (10 m/s²) (102 m) = 102,000 J
KE = ½ (100 kg) (0 m/s)² = 0 J
ME = 102,000 J
B. KE = ½ mv²
18,000 J = ½ (100 kg) v²
v = 60 m/s
ME = 102,000 J
PE = ME − KE = 84,000 J
(100 kg) (10 m/s²) h = 84,000 J
h = 84 m
C. KE = ½ (100 kg) (29 m/s)² = 42,050 J
ME = 102,000 J
PE = ME − KE = 59950 J
(100 kg) (10 m/s²) h = 59950 J
h = 59.95 m
d. PE = (100 kg) (10 m/s²) (60 m) = 60,000 J
ME = 102,000 J
KE = ME − PE = 42,000 J
½ (100 kg) v² = 42,000 J
v = 29.0 m/s
E. PE = (100 kg) (10 m/s²) (0 m) = 0 J
ME = 102,000 J
KE = ME − PE = 102,000 J
½ (100 kg) v² = 102,000 J
v = 45.2 m/s
I believe it’s false, I think I had this before
Answer:
hello your question has some missing parts below is the complete question
and the missing diagram
The two speakers emit sound that is 180° out of phase and of a single frequency,ƒ, Find the lowest two frequencies that produce a maximum sound intensity at the positions of Moe and Curly.
answer : 1316.2 hertz
Explanation:
The frequency that produce the maximum sound intensity can be calculated using the relation below
dsin ∅ = n <em>A</em>
where <em>A = </em>dsin ∅ / n when n = 1 . d = 0.800
<em>A</em> = 0.800 * ( 1 / 3.162 )
<em>A</em> = 0.253 m
speed of sound = 333 m/s
frequency = speed /<em> A</em>
<em>= </em>333 / 0.253 = 1316.2 hertz
Answer:
(3) mass-energy must be conserved
Explanation:
As we know that gamma rays are mass less and charge less photons which will have sufficient energy.
Now in case of Pair production the gamma photons convert its whole energy into mass by the law of Einstein's mass energy equivalence relation.
As per his relation we can say
here we will have
[tex]\Delta m[\tex] = mass produced
now we also have to think that here the two particles must have a pair of particles and antiparticles so that the combined mass system will have energy equivalent to the energy of gamma photons and also it must follow the conservation of charge
So here it will form an electron and a positron such that total charge will be zero and the energy will be same as energy of gamma photon.