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tatiyna
3 years ago
13

Which substance is a gas at 20˚C and one atmosphere of pressure? A. C B. O3 C. Ca D. I2

Chemistry
1 answer:
jasenka [17]3 years ago
3 0

Answer:

O3

Explanation:

The answer to the question is O3 .

Hope this helped! Have an amazing day :)

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If a combination reaction takes place between potassium and chlorine what is the product
zepelin [54]
It would be potassium chloride or kcl
4 0
4 years ago
The diagram below shows a cell placed in a solution.
Sholpan [36]

it will expand as water moves into it.


3 0
3 years ago
Write the formula for potassium oxide. why do you not need prefixes in the name ​
Molodets [167]

Potassium oxide: K₂O.

There's no need for prefixes since K₂O is an ionic compound.

<h3>Explanation</h3>

Find the two elements on a periodic table:

  • Potassium- K- on the left end of period four.
  • Oxygen- O- near the right end of periodic two.

Elements on the bottom-left corner of the periodic table are metals. Those on the top-right corner are nonmetals.

  • Potassium is a metal,
  • Oxygen is a nonmetal.

A metal and a nonmetal combine to form an ionic compound. Potassium oxide is likely to be an ionic compound. It contains two types of ions:

  • Potassium ions: Potassium is group 1 of the periodic table. It is an alkaline metal. Like other alkaline metals such as sodium Na, potassium K tends to lose one electron and form ions of charge +1 in compounds. The ion would be K⁺.
  • Oxide ions from oxygen: Oxygen is the second most electronegative element on the periodic table. It tends to gain two electrons and form the oxide ion \text{O}^{2-} when it combines with metals.

The two types of ions carry opposite charges. They shall pair up at a certain ratio such that they balance the charge on each other. The charge on each \text{O}^{2-} ion is twice that on a \text{K}^{+} ion. Each \text{K}^{+} would pair up with two \text{O}^{2-}. Hence the subscript in the formula: \text{K}_{\bf 2}\text{O}.

There are two classes of compounds:

  • Covalent compounds, which need prefixes, and
  • Ionic compounds, which need no prefix.

Prefixes are needed only in covalent compounds. For instance in the covalent compound carbon dioxide \text{CO}_2, the prefix di- indicates that there are two oxygen atoms in the formula \text{CO}_2. However, there's no need for prefix in ionic compounds such as \text{K}_2\text{O}.

7 0
3 years ago
For SCl4, the electron domain geometry is _______(i)________ and the molecular geometry is ______(ii)________.
Likurg_2 [28]

The electron domain geometry is trigonal bipyramidal while the molecular geometry of the compound is seesaw.

The shapes of molecules is determined by the number of electron pairs on the valence shell of the central atom in the molecule. These electron domains include lone pairs and bond pairs.

The lone pairs only contribute towards the electron domain geometry and not the molecular geometry. SCl4 has five electron domains hence its electron domain geometry is trigonal bipyramidal. The molecular geometry of the compound is seesaw.

Learn more: brainly.com/question/6505878

8 0
3 years ago
A metallurgist has one alloy containing 21% aluminum and another containing 42% aluminum. how many pounds of each alloy must he
Naily [24]
Answer is: 7.8 lb of 21% aluminum and 33.2 ib of <span>42% aluminum.</span>

ω₁<span> = 21% ÷ 100% = 0.21.
ω</span>₂<span> = 42% ÷ 100% = 0.42.
ω</span>₃<span> = 38% ÷ 100% = 0.38.
</span>m₁ = ?.

m₂<span> = ?.
</span>m₃ = m₁ + m₂<span>.
</span>m₃ = 41 pounds.

m₁ = 41 lb - m₂<span>.
ω</span>₁ · m₁ + ω₂ ·m₂ = ω₃ · m₃.

0.21 · (41 lb - m₂) + 0.42 · m₂ = 0.38 · 41 lb.

8.61 lb - 0.21m₂ + 0.42m₂ = 15.58 lb.

0.21m₂ = 6.97 lb.

m₂ = 6.97 lb ÷ 0.21.

m₂ = 33.2 lb.

m₁ = 41 lb - 33.2 lb.

m₁<span> = 7.8 lb.</span>



8 0
3 years ago
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