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Fynjy0 [20]
3 years ago
7

What is the term for a liquid composed of polar molecules?

Chemistry
1 answer:
IrinaVladis [17]3 years ago
7 0
A dissolving liquid composed of polar molecules is a polar solvent.

The distinction of polar and non-polar liquids is important because the like dissolves like rule. This rule states that the solubility is greater when the polarity of the liquid is similar to the polarity of the solute.

So, to dissolve polar compounds (e.g. ionic compounds) you should use polar solvents (e.g. water).

Answer: polar solvent
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Classify each of the following equations as synthesis, decomposition, or replacement.
Sonja [21]

Answer: A. Is decomposition

B. Is synthesis where Na combines with Cl to form NaCl

C. Is single displacement or replacement. Mg displaces Cu.

Explanation:

7 0
3 years ago
A mover packs books, CDs, and DVDs into a moving box. If the box contains 6.5 kg of books, 1.5 kg of CDs, and 2.0 kg of DVDs, wh
IrinaVladis [17]

Answer:

\text{Mass percentage}=\frac{\text{Mass of the substance}}{\text{Total mass}}\times 100

Given: Mass of books = 6.5 kg

Mass of CD's = 1.5 kg

Mass of DVD's = 2.0 kg

Total mass = 6.5 kg + 1.5 kg + 2.0 kg = 10 kg

\text {Mass percentage of books}=\frac{6.5kg}{10kg}\times {100}=65\%

\text {Mass percentage of CD's}=\frac{1.5kg}{10kg}\times {100}=15\%

\text {Mass percentage of DVD's}=\frac{2.0kg}{10}\times {100}=20\%

7 0
3 years ago
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What is the layer of the sun through which energy is transferred away from the core by radiation?
Sidana [21]
<span>The abscission layer is indicated by the letter</span>
6 0
3 years ago
Calculate the entropy change for a process in which 3.00 moles of liquid water at 08c is mixed with 1.00 mole of water at 100.8c
kupik [55]
The question provides the data in an incorrect way, but what the question is asking is for the entropy change when combining 3 moles of water at 0 °C (273.15 K) with 1 mole of water at 100 °C (373.15 K). We are told the molar heat capacity is 75.3 J/Kmol. We will be using the following formula to calculate the entropy change of each portion of water:

ΔS = nCln(T₂/T₁)

n = number of moles
C = molar heat capacity
T₂ = final temperature
T₁ = initial temperature

We can first find the equilibrium temperature of the mixture which will be the value of T₂ in each case:

[(3 moles)(273.15 K) + (1 mole)(373.15 K)]/(4 moles) = 298.15 K

Now we can find the change in entropy for the 3 moles of water heating up to 298.15 K and the 1 mole of water cooling down to 298.15 K:

ΔS = (3 moles)(75.3 J/Kmol)ln(298.15/273.15)
ΔS = 19.8 J/K

ΔS = (1 mole)(75.3 J/Kmol)ln(298.15/373.15)
ΔS = -16.9 J/K

Now we combine the entropy change of each portion of water to get the total entropy change for the system:

ΔS = 19.8 J/K + (-16.9 J/K)
ΔS = 2.9 J/K

The entropy change for combining the two temperatures of water is 2.9 J/K.
3 0
3 years ago
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The chemical definitions of acids and bases for Arrhenius are:
Cloud [144]

Answer:

Explanation:

Arrhenius defined an acid as a substance that interacts with water to produce excess hydrogen ions in aqueous solution.

A base is a substance which interacts with water to yield excess hydroxide ions, in an aqueous solution according to Arrhenius.

Bronsted-Lowry theory defined an acid as a proton donor while a base is a proton acceptor.

6 0
3 years ago
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