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Pie
2 years ago
9

Which of the following measurements is expressed to three significant figures?

Chemistry
1 answer:
matrenka [14]2 years ago
8 0

The answer is C. 7.30 x 10^-7

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What is the mole ratio of H2O to C8H8?
zepelin [54]

Answer:

Mole ratio for a compound

The chemical formula tells us the mole ratio.

CO2 = 1 CO2 molecule : 1 C atom : 2 O atoms.

Mole ratio for a reaction

The balanced chemical reactions tells us.

C12H22O11 + 12 O2  12 CO2 + 11 H2O

1 C12H22O11 molecule: 12 O2 molecules : 12 CO2

molecules : 11 H2O molecules.

Applications of the mole ratio concept

grams <--> moles <--> moles <--> grams

Explanation:

4 0
3 years ago
What is the maximum mass of ethyl alcohol you could boil with 1000 j of heat, starting from 22 ∘c?
kramer

solution:

1000 = m*2400*(78-22) + m*8.79*10^5

1000= 134400m + 879000m

1000= 1030200m

m = 1000/1013400

m= 1013.4 grams

the final answer is 0.9706 grams


5 0
3 years ago
Write a balanced equation for each of these chemical reactions potassium phosphate + calcium nitrate
cupoosta [38]
It forms <span>calcium phosphate and potassium nitrate
</span>2 K3PO4 + 3Ca(NO3)2 --> Ca3(PO4)2 + 6KNO3

7 0
3 years ago
Chlorine is used to disinfect swimming pools. the accepted concentration for this purpose is 1.00 ppm chlorine, or 1.00 g of chl
frez [133]

The accepted concentration of chlorine is 1.00 ppm that is 1 gram of chlorine per million of water.

The volume of water is 2.29\times 10^{4} gal.

Since, 1 gal= 3785.41 mL

Thus, 2.29\times 10^{4} gal=2.29\times 10^{4}\times 3785.41 mL=8.66\times 10^{7}mL

Density of water is 1 g/mL thus, mass of water will be 8.66\times 10^{7}g.

Since, 1 grams of chlorine →10^{6} grams of water.

1 g of water →10^{-6} g of chlorine and,

8.66\times 10^{7}g of water →86.6 g of chlorine

Since, the solution is 9% chlorine by mass, the volume of solution will be:

V=\frac{100}{9}\times 86.6 mL=9.62\times 10^{2} mL

Thus, volume of chlorine solution is 9.62\times 10^{2} mL.

6 0
3 years ago
4. A student purified a 500-mg sample of phthalic acid by recrystallization from water. The published solubility of phthalic aci
kupik [55]

Answer:

2.77 mL of boiling water is the minimum amount which will dissolve 500 mg of phthalic acid.

Explanation:

We know from the problem that 18 g of phthalic acid are dissolved in 100 mL of water at 99 °C.

Now we devise the following reasoning:

If          18 g of phthalic acid are dissolved in 100 mL of water at 99 °C

Then   0.5 g of phthalic acid are dissolved in X mL of water at 99 °C

X = (0.5 × 100) / 18 = 2.77 mL of water

7 0
3 years ago
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