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FinnZ [79.3K]
4 years ago
12

In the PhET simulation window, click the Two Atoms menu in the top left corner of the screen. Click on the partial charges check

box to see the partial charges of the atoms. Vary the electronegativity of atom A and atom B and observe the effects on the partial charge of each accordingly. Use the PhET to complete the sentences describing how electronegativity is related to bond dipole experienced by the molecule.
Chemistry
1 answer:
bearhunter [10]4 years ago
7 0

Answer:

When two atoms with different electronegativities are bonded together, a bond dipole exists. These are displayed with an arrow originating at the atom with the lowest electronegativity and pointing toward the atom with the highest electronegativity.  

Partial charges will exist on each atom when a bond exists between two atoms with different electronegativities. Since the atom with a higher electronegativity will have a stronger ability to attract electron, it will have a partial negative charge. The atom with a lower electronegativity will have an equal and opposite positive charge. As the difference in electronegativity increases, the resulting magnitudes of the partial charges will increase.  

Bond character is used to describe the severity of the electronegativity differences between the two tans involved in a bond. Bonds that have ionic character correspond to a larger difference in electronegativities and covalent bond character corresponds to a smaller difference.  

For example, increasing the electronegativity of an atom A in the PhET simulation and decreasing the electronegativity of atom B will result in a bond that is more ionic in character.  

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Determine the volume of fluid in the graduated cylinder 12.8ml 12.7ml 12.78ml 12.88
liubo4ka [24]

Answer:

the volume is 12.79ml

Explanation:

12.8+12.7+12.78+12.88=51.16

51.16/4

=12.79

8 0
3 years ago
In a single replacement reaction between 2.57 moles Aluminum and 3.59 moles of Hydrochloric acid, how many moles of Hydrogen can
Alenkasestr [34]

Answer:

1.795 mole of H2.

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

2Al + 6HCl —> 2AlCl3 + 3H2

Step 2:

Determination of the limiting reactant.

From the balanced equation above,

2 moles of Al reacted with 6 moles

Therefore, 2.57 moles of Al will react with = (2.57 x 6)/2 = 7.71 moles of HCl.

From the calculation made above, it will require a higher amount of HCl than what was given to react completely with 2.57 moles of Al. Therefore, HCl is the limiting reactant and Al is the excess reactant.

Step 3:

Determination of the number of mole H2 produced from the reaction.

Here, we shall be using the limiting reactant because it will produce the maximum yield of the reaction since all of it were consumed by the reaction.

The limiting reactant is HCl and the amount of H2 produce can be obtained as follow:

From the balanced equation above,

6 moles of HCl reacted to produce 3 moles of H2.

Therefore, 3.59 moles of HCl will produce = (3.59 x 3)/6 = 1.795 mole of H2.

From the calculations made above, 1.795 mole of H2 is produced from the reaction.

5 0
4 years ago
The term element refers to atoms that have the same number of _______.
erica [24]
I guess it’s Electrons
7 0
4 years ago
Read 2 more answers
Write a balanced net ionic equation for the reaction of aqueous solutions of baking soda (NaHCO3) and acetic acid.(A) HCO3–(aq)
IgorC [24]

<u>Answer:</u> The correct answer is Option C.

<u>Explanation:</u>

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of sodium bicarbonate and acetic acid is given as:

NaHCO_3(aq.)+CH_3COOH(aq.)\rightarrow CH_3COONa(aq.)+H_2O(l)+CO_2(g)

Ionic form of the above equation follows:

Na^+(aq.)+HCO_3^-(aq.)+CH_3COO^-(aq.)+H^+(aq.)\rightarrow CH_3COO^-(aq.)+Na^+(aq.)+H_2O(l)+CO_2(g)

As, sodium and acetate ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

HCO_3^-(aq.)+H^+(aq.)\rightarrow CO_2(g)+H_2O(l)

Hence, the correct answer is Option C.

8 0
3 years ago
Determine which of the following pairs of reactants will result in a spontaneous reaction at 25°C. None of the above pairs will
Alla [95]

Answer:

Only Fe^{3+}+Mg gives spontaneous reaction.

Explanation:

A redox reaction will be spontaneous if standard reduction potential (E^{0}) of the reaction is positive. Because it leads to negative standard gibbs free energy change (\Delta G^{0}), which is a thermodynamic condition for spontaneity of a reaction.

E^{0}=E^{0}(reduction)-E^{0}(oxidation)

Where E^{0}(reduction) and E^{0}(oxidation) represents standard reduction potential of reduction half cell and standard reduction potential of oxidation half cell.

(1) Oxidation:         Mg-2e^{-}\rightarrow Mg^{2+} ;  E_{Mg^{2+}\mid Mg}^{0}=-2.38V

Reduction:         Fe^{3+}+3e^{-}\rightarrow Fe ; E_{Fe^{3+}\mid Fe}^{0}=-0.04V

So, E^{0}=E_{Fe^{3+}\mid Fe}^{0}-E_{Mg^{2+}\mid Mg}^{0}=(-0.04+2.38)V=2.34V

Hence this pair will give spontaneous reaction.

(2) Similarly as above, E^{0}=E_{Pb^{2+}\mid Pb}^{0}-E_{Au^{+}\mid Au}^{0}=(-0.13-1.69)V=-1.82 V

Hence this pair will give non-spontaneous reaction.

(3) Similarly as above, E^{0}=E_{Ag^{+}\mid Ag}^{0}-E_{Br_{2}\mid Br^{-}}^{0}=(0.80-1.07)V=-0.27 V

Hence this pair will give non-spontaneous reaction.

(4)  Similarly as above, E^{0}=E_{Li^{+}\mid Li}^{0}-E_{Cr^{3+}\mid Cr}^{0}=(-3.04+0.74)V=-2.30 V

Hence this pair will give non-spontaneous reaction.

6 0
3 years ago
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