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mestny [16]
3 years ago
10

What is the charge of the following polyatomic ions

Chemistry
1 answer:
Veronika [31]3 years ago
3 0

Answer:

D

Explanation:

D

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How many atoms would be contained in 454 grams of iron?
aliina [53]

Answer:

4.90 x 10 24 atoms

Explanation:

the 24 is the exponent for the 10

5 0
2 years ago
PLEASE HELP! I really don’t understand! Thanks!
PIT_PIT [208]

http://century.rochester.k12.mn.us/cms/One.aspx?portalId=3086882&pageId=6133921

Hope this helps!

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6 0
3 years ago
What is the volume of a container that contains 24.0 grams of N2 gas at 328K and 0.884 atm
pychu [463]

Answer:

Explanation:

10L

6 0
2 years ago
Classify each amino acid into the following categories. Select the amino acid that fits best in each category. Each amino acid w
mel-nik [20]

Answer:

1. Lysine

2. Aspartic acid

3. Serine

4. Alanine

5. Tryptophan

Explanation:

Amino acids are biomolecules that contain two functional groups and one R side chain. The two functional groups are: carboxyl group and amino group.

The α-amino acids are the amino acids in which the two functional groups and the R side chain are attached to the α-carbon of the amino acid. They are total 22 α-amino acids.

1. A basic amino acid: Lysine is a positively charged, polar basic amino acid with a lysyl side chain.

2. An acidic amino acid: Aspartic acid is a negatively charged, polar acidic amino acid with an acidic carboxymethyl group.

3. A neutral polar amino acid: Serine is a polar and neutral amino acid with a hydroxymethyl group.

4. A non-polar aliphatic amino acid: Alanine is an aliphatic, nonpolar and neutral amino acid with a methyl side chain.

5. An aromatic amino acid: Tryptophan is an aromatic, nonpolar and neutral amino acid with an indole side chain.

3 0
3 years ago
A sample of gas with an initial volume of 12.5 L at a pressure of 784 torr and a temperature of 295 K is compressed to a volume
Kipish [7]

Answer:

Final pressure in (atm) (P1) = 6.642 atm

Explanation:

Given:

Initial volume of gas (V) = 12.5 L

Pressure (P) = 784 torr

Temperature (T) = 295 K

Final volume (V1) = 2.04 L

Final temperature (T1) = 310 K

Find:

Final pressure in (atm) (P1) = ?

Computation:

According to combine gas law method:

\frac{PV}{T} =\frac{P1V1}{T1} \\\\\frac{(784)(12.5)}{295} =\frac{(P1)(2.04)}{310}\\\\33.22 = \frac{(P1)(2.04)}{310}\\\\P1=5,048.18877

⇒ Final pressure (P1) = 5,048.18877 torr

⇒ Final pressure in (atm) (P1) = 5,048.18877 torr / 760

⇒ Final pressure in (atm) (P1) = 6.642 atm

3 0
3 years ago
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