What is the charge of the following polyatomic ions

4.14 Oxygen requirement for growth on glycerol Klebsiella aerogenes is produced from glycerol in aerobic culture with ammonia as

Iteru [2.4K]

Answer:

0.37 g

Explanation:

The molecular weight for Glycerol = 92

Number of Carbon atoms in glycerol (x) $C_3H_8O_3$ = 3

Molecular weight of the Biomass ( Klebsiella aerogenes )

= $CH_{1.73}O_{0.43}N_{0.24}$

= $\frac{23.97}{0.92}$

= 26.1

From the molecular weight of the Biomass, we can deduce the Degree of reduction for the substrate(glycerol denoted as $\delta _g$ ) as follows:

= (4×1)+(1×1.73)-(2×0.43)-(3×0.24)

= 4.15

Given that the yield of the Biomass = 0.40 g

However;

C = $Yield of Biomass *\frac{Molecular weight of substrate}{Molecular weight of the Biomass}$

C = $0.40*\frac{92}{26.1}$

C = 1.41 g

Now , the oxygen requirement can be calculated as:

= $\frac{1}{4}*(n*S - C * \delta _{g})$

= $\frac{1}{4}(3*4.7-1.41*4.15)$

= 2.1 g/mol

Hence, we can say that the needed oxygen = 2.1 g/mol of the substrate consumed.

Now converting it to mass terms; we have:

= $2.1*\frac{number of mole of oxygen}{molecular weight of glycerol}$

= $2.1 * \frac{16}{92}$

= 0.3652 g

≅ 0.37 g

∴ The oxygen requirement for this culture in mass terms = 0.37 g

3 0

3 years ago

Which of the following solutions will freeze at the lowesttemperature? a.1 mole C6H12O6in 500 g water b.1 mole MgF2in 500 g wate

AlladinOne [14]

Answer:

Option d.

1 mole AlCl3in 500 g water

Explanation:

ΔT = Kf . m . i

Freezing T° of solution = - (Kf . m . i)

In order to have the lowest freezing T° of solution, we need to know which solution has the highest value for the product (Kf . m . i)

Kf is a constant, so stays the same and m stays also the same because we have the same moles, in the same amount of solvent. In conclussion, same molality to all.

i defines everything. The i refers to the Van't Hoff factor which are the number of ions dissolved in solution. We assume 100 & of ionization so:

a. Glucose → i = 1

Glucose is non electrolytic, no ions formed

b. MgF₂ → Mg²⁺ + 2F⁻

i = 3. 1 mol of magnessium cation and 2 fluorides.

c. KBr → K⁺ + Br⁻

i = 2. 1 mol potassium cation and 1 mol of bromide anion

d. AlCl₃ → Al³⁺ + 3Cl⁻

i = 4. 1 mol of aluminum cation and 3 mol of chlorides.

Kf . m . 4 → option d will has the highest product, therefore will be the lowest freezing point.

5 0

3 years ago

Read 2 more answers

Write balanced equations and Kb expressions for these Brønsted-Lowry bases in water:(CH₃)₃N

grandymaker [24]

(CH3)3N + H2O ---> (CH3)3NH+ + OH-

The equation of Kb:

Kb = [(CH3)3NH+][OH-]/[(CH3)3N]

<h3>What do we know about the process of dissolution?</h3>

A solute can dissolve in a solvent in a solid, liquid, or gaseous phase to create a solution through the process of dissolution. Solubility. The greatest amount of a solute that may dissolve in a solvent at a particular temperature is known as its solubility. The solution is said to as saturated when the maximum amount of solute is present.