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Arte-miy333 [17]
3 years ago
9

The eye is connected to the brain by nerves. A. True B. False

Chemistry
2 answers:
Vikentia [17]3 years ago
4 0

the answer is A..which is true

Sunny_sXe [5.5K]3 years ago
3 0
Your question answer is true The optic nerve connects the retina to the visual cortex in the back of the brain.
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Identify each property below as more characteristic of a metal or a nonmetal.
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A. Nonmetallic
B. Nonmetallic
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3 years ago
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Describe the relative charge, relative mass and location of a proton.
Molodets [167]
The relative charge of a proton is +1. The relative mass of a proton is 1. The location of a proton is in the nucleus of an atom.
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3 years ago
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Calculate the number of grams in sodium in 7.6g of Na2C6H6O7 (sodium hydrogen citrate) express your answer using two significant
Katen [24]

Answer:

Explanation:

the molecular mass of Na2C6H6O7 =236 g\mole it has a sodium that has 23 g/mole so 7.6 g of Na2C6H6O7 has x of sodium mass

  236 g/mole ⇒  23g/mole

<h2>   7.6 g  ⇒    ˣ    </h2>

7.6 x 23 ÷ 236  = 74.07×10-2 grams of sodium

<h2 />
7 0
3 years ago
A 10.0 mL sample of 0.25 M NaOH(aq) is titrated with 0.10 M HCl(aq) (adding HCl to NaOH). Determine which region on the titratio
Anna11 [10]

Answer:

1) After adding 15.0 mL of the HCl solution, the mixture is before the equivalence point on the titration curve.

2) The pH of the solution after adding HCl is 12.6

Explanation:

10.0 mL of 0.25 M NaOH(aq) react with 15.0 mL of 0.10 M HCl(aq). Let's calculate the moles of each reactant.

nNaOH=\frac{0.25mol}{L} .10.0 \times 10^{-3} L=2.5 \times 10^{-3}mol

nHCl=\frac{0.10mol}{L} \times 15.0 \times 10^{-3} L=1.5 \times 10^{-3}mol

There is an excess of NaOH so the mixture is before the equivalence point. When HCl completely reacts, we can calculate the moles in excess of NaOH.

                    NaOH       +       HCl       ⇒       NaCl      +         H₂O

Initial          2.5 × 10⁻³         1.5 × 10⁻³               0                      0

Reaction    -1.5 × 10⁻³        -1.5 × 10⁻³          1.5 × 10⁻³          1.5 × 10⁻³

Final            1.0 × 10⁻³               0                 1.5 × 10⁻³          1.5 × 10⁻³

The concentration of NaOH is:

[NaOH]=\frac{1.0 \times 10^{-3} mol }{25.0 \times 10^{-3} L} =0.040M

NaOH is a strong base so [OH⁻] = [NaOH].

Finally, we can calculate pOH and pH.

pOH = -log [OH⁻] = -log 0.040 = 1.4

pH = 14 - pOH = 14 - 1.4 = 12.6

5 0
3 years ago
Which technology was essential for the development of the cell theory?​
vodka [1.7K]

Answer: Microscope

Explanation: This is a kid answering :)

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