The mass of the piece of wood is 35.58 g.
Joule = M × T × C
Where, M = mass
T = change in temperature(42C-23C=19 C)
C = specific heat capacity = 1.716 joules/gram
Substituting the values in the equation,
1160 = M × 19 × 1.716
M = 1160/32.604 = 35.58 g
Therefore, the mass of the piece of wood = 35.58 g
<h3>What is meant by specific heat capacity?</h3>
A material's specific heat capacity, which is defined as its heat capacity divided by its mass, determines how much energy is required to increase a gram's temperature by one degree Celsius (or one Kelvin)
<h3>What is mass?</h3>
Mass is the quantity of matter in a physical body.
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Answer:
A bowling ball is a ball that is used in the game of bowling, where you roll the ball down an aisle and try to knock down as many pins as you can.
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Explanation:
The five common acids are sulfuric acid, hydrochloric acid, nitric acid, lactic acid, and acetic acid.
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Answer:
Empirical formula: BH3
Molecular Formula: B2H6
Explanation:
To solve the exercise, we need to know how many boron atoms and how many hydrogen atoms the compound has. We know that of the total weight of the compound, 78.14% correspond to boron and 21.86% to hydrogen. As the weight of the compound is between 27 g and 28 g, using the above percentages we can solve that the compound has between 21.1 g and 21.8 g of boron, and between 5.9 g and 6.1 g of hydrogen:
100% _____ 27 g
78.14% _____ x = 78.14% * 27g / 100% = 21.1 g boron
100% ______27 g
21.86% ______ x = 21.86% * 27g / 100% = 5.9 g hydrogen
100% _____ 28 g
78.14% _____ x = 78.14% * 28g / 100% = 21.8 g boron
100% _____ 28g
21.86% _____ x = 21.86% * 28g / 100% = 6.1 g hydrogen
So, if the atomic weight of boron is 10.8 g, there must be two boron atoms in the compound that sum 21.6 g. The weight of hydrogen is 1 g, so the compound must have six hydrogen atoms.
The molecular formula represents the real amount of atoms that form a compound. Therefore, the molecular formula of the compound is B2H6.
The empirical formula is the minimum expression that represents the proportion of atoms in a compound. For example, ethane has 2 carbon atoms and 6 hydrogen atoms, so its molecular formula is C2H6, however, its empirical formula is CH3. Therefore, the empirical formula of the boron compound is BH3.
