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3 years ago

What is the mass number of 80Br

Chemistry

1 answer:

Amanda [17]3 years ago

4 0

Mass number of an element write in bottom of it!

So, there 80 would be the mass number of ₈₀Br.

Hope this helps!

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A graduated cylinder is filled to the 40.00-mL mark with a mineral oil. The masses of the cylinder before and after the addition

castortr0y [4]

Answer:

Firstly, Let's experiment this !

Experiment 1 :

159.446g - 124.966g = 34.48g

34.48g = The mass of Mineral oil.

The density of the mineral oil = M/V = 34.48g/40mL = 0.862g/cm³.

Experiment 2 :

124.966 + 18.173 = 143.139 = The mass of solid + cylinder.

124.966 + 50.952 = 175.918 = The mass of solid + cylinder + Mineral water.

175.918 - 143.139 = 32.779 = The mass of added mineral oil.

Explanation:

Now we have to find the volume of the added mineral oil using the density from experiment 1.

V = 32.779g/0.862g/cm³ = 38.02668213mL

Since we found the volume of the solid, we then have to subtract the added mineral oil volume from the total volume from experiment 1.

Volume of solid = 40-38.02668213 = 1.97331787mL

Density of solid = 18.713g/1.97331787mL = 9.483013499g/cm^3

1.97331787 = (4/3)(3.14)r³

1.97331787*(3/4)(3.14) = .4713338861

.4713338861 = r ³

r = 0.7782328425158433

r = 0.78

Now that's our final answer ! r = 0.78

5 0

2 years ago

For the following SN1 solvolysis reaction, select the correct rate equation and the overall reaction order (note: CH3OH is the s

sineoko [7]

Answer:

Explanation:

rate = K[(CH3)3CCl]

overall order is also first order

Since we are told that CH3OH is the solvent for the reaction, as such the rate law equation will only be written for (CH3)3CCl .

8 0

2 years ago

One of the reactions in a blast furnace used to reduce iron is shown above. How many grams of Fe2O3 are required to produce 15.5

Salsk061 [2.6K]

Answer : The correct option is, (b) 22.1 g

Solution : Given,

Mass of iron = 15.5 g

Molar mass of iron = 56 g/mole

Molar mass of $Fe_2O_3$ = 160 g/mole

First we have to calculate the moles of iron.

$\text{Moles of Fe}=\frac{\text{Mass of Fe}}{\text{Molar mass of Fe}}=\frac{15.5g}{56g/mole}=0.276moles$

Now we have to calculate the moles of $Fe_2O_3$ .

The balanced reaction is,

$Fe_2O_3+3CO\rightarrow 2Fe+3CO_2$

From the balanced reaction, we conclude that

As, 2 moles of iron obtained from 1 mole of $Fe_2O_3$

So, 0.276 moles of iron obtained from $\frac{0.276}{2}=0.138$ mole of $Fe_2O_3$

Now we have to calculate the mass of $Fe_2O_3$

$\text{Mass of }Fe_2O_3=\text{Moles of }Fe_2O_3\times \text{Molar mass of }Fe_2O_3$

$\text{Mass of }Fe_2O_3=(0.138mole)\times (160g/mole)=22.08g=22.1g$

Therefore, the amount of $Fe_2O_3$ required are, 22.1 grams.

6 0

3 years ago

How many grams are in one mole of lead?

mariarad [96]

The answer is 207.2 grams.

5 0

3 years ago

Read 2 more answers

What is the barometric pressure exerted in pascals (Pa) of a column of decane (density = 0.7300 g/cm3) 636.2 mm in height?

BartSMP [9]

<h3>Answer:</h3>

4551.37 Pascals

<h3>Explanation:</h3>

The pressure refers to the force exerted by a substance per unit area.

The pressure is liquid is calculated by;

P = height × density × gravitational acceleration

In this case;

Height = 636.2 mm

Density = 0.7300 g/cm³

g = 9.8 N/kg

We need to convert mm to m and g/cm³ to kg/m³

Therefore;

Height = 636.2 mm ÷1000

= 0.6362 m

Density = 0.73 g/cm³ × 1000 kg/m³

= 730 kg/m³

Then, we can calculate the pressure;

Pressure = 0.6362 m × 730 kg/m³ × 9.8 N/kg

= 4551.3748 pascals

= 4551.37 Pascals

Therefore, the pressure of the column of decane is 4551.37 Pascals

5 0

2 years ago