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masya89 [10]
3 years ago
15

Which part of the atom cannot have its location accurately determined and is modeled by a cloud around the center of the atom? A

) electron B) neutron C) nucleus D) proton
Chemistry
2 answers:
drek231 [11]3 years ago
5 0

Answer:

THE ANSWER IS <em>A)ELECTRON</em>

<em>Explanation:</em>

Tju [1.3M]3 years ago
3 0

Answer:

Electron

Explanation:

The answer would be the electron because it is constantly moving so its location cannot be accurately determined

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Consider this reaction: Upper K Upper O Upper H + Upper H Upper B 4 right arrow Upper K Upper B r + Upper H Subscript 2 Baseline
Juliette [100K]
Hbr is the answer when I work it out that’s what I got.
4 0
3 years ago
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What is the freezing point of an aqueous solution that has 25.00 g of calcium iodide dissolved in 1250 g of water?
ozzi

Answer:

<u></u>

  • <u>- 0.380ºC</u>

Explanation:

The lowering of the freezing point of a solvent is a colligative property ruled by the formula:

  • \Delta T_f=K_f\times m\times i

Where:

  • ΔTf is the lowering of the freezing point
  • Kf is the molal freezing constant of the solvent: 1.86 °C/m
  • m is the molality of the solution
  • i is the van't Hoff factor: the number of particles (ions) per unit of ionic compound.

<u />

<u>a) molality, m</u>

  • m = number of moles of solute/ kg of solvent
  • number of moles of CaI₂ = mass in grams/ molar mass
  • number of moles of CaI₂ = 25.00g / 293.887 g/mol = 0.0850667mol
  • m = 0.0850667mol/1.25 kg = 0.068053m

<u>b) i</u>

  • Each unit of CaI₂, ideally, dissociates into 1 Ca⁺ ion and 2 I⁻ ions. Thus, i = 1 + 2 = 3

<u />

<u>c) Freezing point lowering</u>

  • ΔTf =  1.86 °C/m × 0.068053m × 3 = 0.3797ºC ≈ 0.380ºC

<h2>I have problems to upload the full answer in here, so I attach a pdf file with the whole answer.</h2>
Download pdf
6 0
3 years ago
HELP ASAP!!! #2 only please.
shtirl [24]

Answer:

friend me on here and imma send you the link Explanation:

6 0
3 years ago
Read 2 more answers
What is the boiling point of 0.464 m lactose in water? (Kb of water = 0.512 oC/m). Enter your answer to 3 decimal places.
kirill [66]

Answer:

Boiling point for the solution is 100.237°C

Explanation:

We must apply colligative property of boiling point elevation

T° boiling solution - T° boiling pure solvent = Kb . m

m = molalilty (a given data)

Kb = Ebulloscopic constant (a given data)

We know that water boils at 100°C so let's replace the information in the formula.

T° boiling solution - 100°C = 0.512 °C/m . 0.464 m

T° boiliing solution = 0.512 °C/m . 0.464 m + 100°C → 100.237 °C

3 0
3 years ago
8.) If 396 g of Carbon Dioxide (CO2) are produced, what mass of Oxygen
KengaRu [80]

Answer:

480 g of oxygen.

Explanation:

C3H8 + 5O2 --->  3CO2 + 4H2O

Using the molar masses:

3*12 + 6*16 g of CO2 were formed from 10*16 g O2

132g  g CO2 from 160 g O2

1g CO2 from (160/132) g O2

396 g from (160/132) * 396

= 480 g of oxygen.

3 0
3 years ago
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