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stealth61 [152]
3 years ago
11

1 Which best defines concentration?A ratio that describes the amount of solute divided by the amount of solvent or solutionB rat

io that describes the amount of solvent or solution divided by the amount of solute C ratio that describes the mass of solute divided by the mass of solvent D ratio that describes the amount of solvent in a solution 2 Which contributes to the dissolution of sugar in water?A the dissociation of an ionic compound in waterB a strong pull of water molecules on an ionic compoundC the dissociation of a polar covalent compound in waterD a strong pull of water molecules on a polar covalent compound
Chemistry
1 answer:
Alenkasestr [34]3 years ago
4 0

1 Which best defines concentration?A ratio that describes the amount of solute divided by the amount of solvent or solutionB ratio that describes the amount of solvent or solution divided by the amount of solute C ratio that describes the mass of solute divided by the mass of solvent D ratio that describes the amount of solvent in a solution

ANSWER: (A) ratio that describes the amount of solute divided by the amount of solvent or solution

2 Which contributes to the dissolution of sugar in water?A the dissociation of an ionic compound in waterB a strong pull of water molecules on an ionic compoundC the dissociation of a polar covalent compound in waterD a strong pull of water molecules on a polar covalent compound

ANSWER: (D) a strong pull of water molecules on a polar covalent compound

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What is the percent abundance of Pt-198, if the average atomic mass of platinum is 195.16 and platinum has four naturally occurr
nlexa [21]

Answer:

Explanation:

8%

5 0
3 years ago
12.5 g of copper are reacted with an excess of chlorine gas, and 25.4 g of copper(II) chloride are
Alika [10]

Answer:

Percent yield = 94.5%

Theoretical yield =  26.89 g

Explanation:

Given data:

Mass of copper = 12.5 g

Mass of copper chloride produced = 25.4 g

Theoretical yield = ?

Percent yield = ?

Solution:

Cu + Cl₂  →  CuCl₂

Number of moles of Copper:

Number of moles = mass/ molar mass

Number of moles = 12.5 g/ 63.55 g/mol

Number of moles = 0.2 mol

Now we will compare the moles of copper with copper chloride.

          Cu          :           CuCl₂

           1             :              1

          0.2          :            0.2

Theoretical yield:

Mass of copper chloride:

Mass = Number of moles × molar mass

Mass = 0.2 mol × 134.45 g/mol

Mass = 26.89 g

Percent yield:

Percent yield = Actual yield / theoretical yield  × 100

Percent yield = 25.4 g/26.89 g × 100

Percent yield = 94.5%

8 0
4 years ago
Calculate the volume (in cm³) of 38.5 grams of platinum if the density of platinum is 21.5 g/cm³. Give your answer to 2 decimal
Gennadij [26K]

Answer:

\boxed {\boxed {\sf v\approx  1.79 \ cm^3}}

Explanation:

The formula of density is:

d=\frac{m}{v}

If the formula is rearranged for volume, it becomes:

v=\frac{m}{d}

The mass of the platinum is 38.5 grams.

The density is 21.5 grams per cubic centimeter.

m=38.5 \ g \\d= 21.5 \ g/cm^3

Substitute the values into the formula.

v=\frac{38.5 \ g}{ 21.5 \ g/cm^3}

Divide. Note that the grams (g) will cancel each other out.

v=1.79069767 \ cm^3

Round to 2 decimal places (hundredth place). The 0 in the thousandth place tells us to leave the 9 in the hundredth place.

v\approx  1.79 \ cm^3

The volume is about <u>1.79 cubic centimeters.</u>

6 0
3 years ago
Read 2 more answers
Stock solutions are highly concentrated solutions regularly made in laboratories to reduce preparation time and must be diluted
Paraphin [41]

Answer:

0.9 L.

Explanation:

The following data were obtained from the question:

Molarity of stock solution (M1) = 10 M

Molarity of diluted solution (M2) = 1 M

Volume of stock solution (V1) = 100 mL

Volume of water needed =.?

Next, we shall determine the volume of the diluted solution. This can be obtained as follow:

Molarity of stock solution (M1) = 10 M

Molarity of diluted solution (M2) = 1 M

Volume of stock solution (V1) = 100 mL

Volume of diluted solution (V2) =.?

M1V1 = M2V2

10 × 100 = 1 × V2

1000 = V2

V2 = 1000 mL

Next, we shall determine the volume of water needed. This can be obtained as follow:

Volume of stock solution (V1) = 100 mL

Volume of diluted solution (V2) = 1000 mL

Volume of water needed =?

Volume of water needed = (Volume of diluted solution) – (Volume of stock solution)

Volume of water needed = V2 – V1

Volume of water needed = 1000 – 100

Volume of water needed = 900 mL

Finally, we shall convert 900 mL to litre (L). This can be obtained as follow:

1000 mL = 1 L

Therefore,

900 mL = 900 mL × 1 L / 1000 mL

900 mL = 0.9 L

Therefore, the volume of water needed to dilute the solution is 0.9 L.

3 0
3 years ago
What type of energy for a spring is compressed
Firlakuza [10]

Answer:

potential energy is answer

Explanation:

7 0
3 years ago
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